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Margarita [4]
3 years ago
6

STOP IGNORING ME AND HELP ME NOW

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0

Answer:

about $1148.06

Step-by-step explanation:

Your goal is to find the area of the island of grass and multiply that area by the cost per square yard.

Area = radius * radius * pi

You are told that the <em>diameter = 15 yards</em>. We also know that the radius that we need is half of the diameter. <em><u>Radius = 7.5 yards</u></em>.

This means that the <em>Area = 7.5 * 7.5 * 3.14 = 176.625 square yards</em>

Then we multiply by the cost per square yard:

176.625 * 6.50 = 1148.06 is your answer

olya-2409 [2.1K]3 years ago
3 0
Answer:
Will cost about $1148.62
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Help please i really really really need it.....
ruslelena [56]

A)

s = sweater

j = jeans

Equations:

4s + 2j = 140

2s + 3j = 150

B)

4s + 2j = 140

2s + 3j = 150

Multiply (-2) to the second equation

-2 (2s + 3j = 150)

-4s - 6j = -300

Now you have the equations:

4s + 2j = 140

-4s - 6j = -300

-----------------------------add

-4j = -160

  j = 40

4s + 2(40) = 140

4s + 80 = 140

4s = 60

 s = 15

The cost for a sweater is $15 and the cost for a jean is $40

We used the elimination method to solve the system of equations.

C)

Each pair of jean, she will buy 3 sweaters so total = 40 + 3(15) = $85

Total cost for 1 pair of jeans and 3 sweaters = $85

If she has $225 the

$225 / $85 = 2.64

2 jeans = 2 x 40 = $80

6 sweaters = 6 x $15 = $90

So She can only buy 2 jeans and 6 sweaters

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3 years ago
Write and solve a real-world problem that represents the following one-variable inequality.
serg [7]
Hello there! An example problem for this could be:
Emile is looking for a cell-phone plan. His two options are one that costs $40 up front, and costs $0.01 per text, represented by x. The second one is 15 dollars up front and costs $0.06 for each text message. Emile figures that for the first package he has to send 500 texts or more to make it less than the second one. 
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Step-by-step explanation:

I hope you get it right! Please give me brainliest!

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