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babymother [125]
3 years ago
11

What is the distance between the points (4,3) and (1,1) on the cordinate plane

Mathematics
1 answer:
JulsSmile [24]3 years ago
5 0
Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(4,3)....x1 = 4 and y1 = 3
(1,1)...x2 = 1 and y2 = 1
now we sub
d = sqrt (1 - 4)^2 + (1 - 3)^2
d = sqrt (-3^2) + (-2^2)
d = sqrt (9 + 4)
d = sqrt 13
d = 3.61
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3 years ago
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Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
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