What is the distance between the points (4,3) and (1,1) on the cordinate plane

1 answer:

5 0

Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(4,3)....x1 = 4 and y1 = 3
(1,1)...x2 = 1 and y2 = 1
now we sub
d = sqrt (1 - 4)^2 + (1 - 3)^2
d = sqrt (-3^2) + (-2^2)
d = sqrt (9 + 4)
d = sqrt 13
d = 3.61

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Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
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