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babymother [125]
3 years ago
11

What is the distance between the points (4,3) and (1,1) on the cordinate plane

Mathematics
1 answer:
JulsSmile [24]3 years ago
5 0
Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(4,3)....x1 = 4 and y1 = 3
(1,1)...x2 = 1 and y2 = 1
now we sub
d = sqrt (1 - 4)^2 + (1 - 3)^2
d = sqrt (-3^2) + (-2^2)
d = sqrt (9 + 4)
d = sqrt 13
d = 3.61
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Solve the system of equations. y = 7x + 43 y = 2x + 13 a. ( -6, 1) c. ( 6, 1) b. ( 6, -1) d. No solution
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Hello there!

y = 7x + 43
y = 2x + 13

We wanna solve y = 7x + 43 for y in y = 2x + 13

What does that even mean? Well it simply means that we gonna replace y by 7x + 43.

y = 2x + 13

7x + 43 = 2x + 13

Subtract 2x on both sides

7x + 43 - 2x = 2x + 13 - 2x

5x + 43 = 13

Now we can subtract 43 on both sides

5x + 43 - 43 = 13 - 43

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Then divide both sides by 5

5x/5 = -30/5

x = -6

Now since we have the value for x, we gonna use that value to find y.

We can do that by substituting -6 for x in y = 7x + 43

But what does that mean? It means that in y = 7x + 43, we gonna replace the x by -6

y = 7x + 43

y  = 7(-6) + 43

y = -42 + 43

y = 1

Thus,

The answer is: x = -6 and y = 1

The correct answer is option A (-6,1).

Let me know if you have questions about the answer. As always, it is my pleasure to help students like you.
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