Answer:
62.4 square centimeters
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The surface area of the triangular pyramid is equal to the area of the triangular base plus the area of its three lateral triangular faces
In this problem the triangles are equilateral, that means, the
surface area is equal to the area of four congruent equilateral triangles
so
![A=4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=A%3D4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have

substitute
![A=4[\frac{1}{2}(6)(5.2)]=62.4\ cm^2](https://tex.z-dn.net/?f=A%3D4%5B%5Cfrac%7B1%7D%7B2%7D%286%29%285.2%29%5D%3D62.4%5C%20cm%5E2)
Remember, you can do ANYTHING to an equaiton as long as you do it to BOTH SIDES
we can try to get k by itself bymaking that -17 into 0 since k+0=k
-17+17=0 right so
K-17=-12
add 17 to BOTH SIDES
K+17-17=17-12
K+0=5
K=5
3+2•6/3
first you multiply the 2 and 6 on the top to get 12
so now it’s
3+12/3
now add the 12 and 3
15/3
now divide
so your answer is 5
19750 * 0.8 = 15800
15800 / 26 = 607.69
Answer is A