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Basile [38]
3 years ago
10

The length of one edge of a cube is 5 units. what is the volume of this cube in cubic units

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer: the answer is 125 i think

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Find the surface area of the triangular prism shown below .
Wewaii [24]

Answer:

the surface area should be 544 (whatever the unit is)

Step-by-step explanation:

You start by taking the rectangles on the side and finding their area.

1. (10×14)×2 ←Because there are two rectanglular sides.

2. find the area of the triangles on the side. 1/2bh = area of triangle.

(.5×8×6)×4 ← in order to find the area for all of the triangles.

3.  lastly take the base of the prism and find the area then add the previously found values together.

(12×14)+(.5×8×6)×4+ (10×14)×2 = 544

7 0
3 years ago
PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)
ExtremeBDS [4]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 3 &,& -4~) 
%  (c,d)
&&(~ 5 &,& 1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}

\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby 
\begin{array}{llll}
\textit{now let's multiply both}\\
\textit{sides by }\stackrel{LCD}{2}
\end{array}
\\\\\\
2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}
\\\\\\
\textit{and if we multiply both sides by -1}\qquad 5x-2y=23

side note:  multiplying by the LCD of both sides is just to get rid of the denominators
5 0
3 years ago
Y=2x+1
yan [13]

Answer:

(1) 2 (2) (-1/2,0) (3) (0,1)

Step-by-step explanation:

The slope of the line is the number times x. This equation is y=mx+b, where m is the slope and b is the y-intercept. In this case, m is 2, so we have our slope. The y-intercept is easy, as we already know it to be (0,1). The x-intercept is the point where the line hits x when y=0. To solve for the x-intercept, we set y to 0 and solve. We have 0=2x+1. First, we subtract 1 from both sides and get -1=2x. Next, to get x by itself, divide both sides by 2. Now we have -1/2=x. Now we have our x coordinate for our x-intercept. Because of this, we get (-1/2,0) as our x-intercept.

3 0
3 years ago
Given J(1,4) and the midpoint is M(2, 1), find the other endpoint K.
Marina CMI [18]
3, if you do the y^2-y^1/x^2-x^1 you will get 3/1 which will be simplified to 3.
6 0
4 years ago
Find the polynomial of lowest degree with only real coefficients and having the given zeros. -7i and square root of 2
mario62 [17]

Answer:

x³ - (√2)x² + 49x - 49√2

Step-by-step explanation:

If one root is -7i, another root must be 7i.  You can't just have one root with i.  The other roos is √2, so there are 3 roots.  

x = -7i       is one root,

   (x + 7i) = 0    is the factor

x = 7i       is one root

  (x - 7i) = 0     is the factor

x = √2      is one root

    (x - √2) = 0   is the factor

So the factors are...

(x + 7i)(x - 7i)(x - √2) = 0

Multiply these out to find the polynomial...

(x + 7i)(x - 7i) =  x² + 7i - 7i - 49i²

Which simplifies to

  x² - 49i²        since i² = -1 , we have

    x² - 49(-1)  

 

      x² + 49

Now we have...

(x² + 49)(x - √2) = 0

Now foil this out...

 x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0

     x³ + (√2)x² + 49x - 49√2

7 0
3 years ago
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