Math whizzes assemble! this is a tough one, this is a question on my study guide its a screenshot, any help would be appreciated
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1 answer:
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The kinetic energy of the safe increases the force exerted by the concrete
to several times the weight of the safe.
- The magnitude of the force exerted on the safe by the concrete on the is approximately
- The concrete exerts a <u>force</u> that is approximately <u>1,359.16 times the weight of the safe</u>.
Reasons:
First part
The mass of the steel safe, m = 2,200 kg
Velocity of the safe just before it hits the concrete, v = 40 m/s
The amount by which the safe was compressed, d = 0.06 m
The kinetic energy, K.E., of the safe just before it hits the round is therefore;
Work done by concrete, W = Force, F × Distance, d
By the law of conservation of energy, we have;
The work done by the concrete, W = The kinetic energy, K.E. given by the safe
W = K.E. = 1,760,000 J
The effect of the work = The change in the height of the safe
Therefore;
The distance, <em>d</em>, over which the force of the concrete is exerted = The change in the height of the safe = 0.06 m
d = 0.06 m
Therefore;
- The force of the concrete on the safe =
Second part:
The gravitational force of the Earth on the safe, W = The weight of the safe
W = Mass, m × Acceleration due to gravity, g
W = 2,200 kg × 9.81 m/s² ≈ 21,582 N
The ratio of the force exerted by the concrete to the weight of the safe is found as follows;
- The <u>force</u> exerted by the concrete is approximately <u>1,359.16 times the weight of the safe</u>.
Learn more here:
Answer:
Step-by-step explanation:
∠CBA + ∠ABD = 180 {linear pair}
2x - 6 + x +1 = 180
3x -5 = 180
3x = 180 +5
3x = 185
x = 185/3
x = 61 2/3
14.6666666667
Step-by-step explanation:
2•10=20/1/3=6.66666666667+8 is that but you can write it like 14.6 with _ that on top
