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Ber [7]
3 years ago
14

Sunshine High School claims that 72% of its students complete their homework on a daily basis. Ms. Carter surveyed 80 students a

nd found that only 60% complete their daily homework. What does the test statistic calculation look like in this situation for an appropriate hypothesis test? z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80 z equals 0.60 minus 0.72 all over the square root of the quantity 0.60 times 0.40 over 80
Mathematics
1 answer:
Ulleksa [173]3 years ago
6 0

Answer: z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

Step-by-step explanation:

let p be the population proportion of students complete their homework on a daily basis.

As per given , we have

p= 0.72

sample size : n= 80

Sample proportion : \hat{p}=0.60

Test statistic for proportion:

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

i.e.

z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(1-0.72)}{80}}}

i.e.

z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(0.28)}{80}}}

That is , z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

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Read 2 more answers
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What is your question?

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3 years ago
I NEED HELP WITH THESE TWO QUESTIONS PLZ DO NOT ANSWER IF YOU CANNOT EXPLAIN THE ANSWER
Murljashka [212]

9514 1404 393

Answer:

  1. asymptotes: x=-6, x=6, y=0; zero: x=0

  2. 20 blue fish

Step-by-step explanation:

1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.

The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.

The zero is where the numerator is zero, at x=0.

In summary:

  • vertical asymptotes: x = ±6
  • horizontal asymptote: y = 0
  • zero: (0, 0)

__

2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.

  blue fish = 2×10 = 20 fish

<em><u>Check</u></em>

There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.

<u><em>Additional comment</em></u>

I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...

  r = 60%(r + b) . . . . reds are 60% of the total

  r - b = 10 . . . . . . . . 10 more reds than blues

We want the value of b, so we can eliminate r by substituting for it:

  r = 10 + b . . . . from the second equation above

  (10 +b) = 0.60((10 +b) + b) . . . . substitute for r

  10 +b = 6 + 1.2b . . . simplify

  4 = 0.2b . . . . subtract b+6

  20 = b . . . . . . multiply by 5 (there are 20 blue fish)

6 0
3 years ago
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