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Alexxandr [17]
3 years ago
14

Graph the line: y=2/3x-4​

Mathematics
2 answers:
Likurg_2 [28]3 years ago
5 0
Graph the line using the slope and y-intercept, or two points.
Slope:
2
3
2
3
y-intercept:
(
0
,
−
4
)
(
0
,
-
4
)
x
y
0
−
4
3
−
2
kompoz [17]3 years ago
5 0

slope: -\frac{3}{2}

y-intercept: (0, -4) (answer let me know if i am wrong)

Y=2/3x-4 is in Slope - intercept form meaning you are shown the slope (how steep the line is) and the y intercept (where the equation hits the vertical axis)

With the given information, select the point (0, -4) on the graph, this is where the line crosses the y axis, as shown through the -4 in the equation.

Next, look at the slope and you'll see 2/3x. Slope is in format "rise over run" meaning the first number (2) is the vertical change, so up two, and the second number (3) is horizontal change, right 3.

Combine these two steps together and select point (0. -4) then the next point should be at (3,2), 2 units up and three to the right from the y intercept.

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Li deposited $17,500 into a bank account that earned simple interest each year. After 2 years, he had earned $2975 in interest.
Keith_Richards [23]

Answer:

The annual interest rate was $1487.50

Step-by-step explanation:

All you do is 2975 divided by2=1487.50

4 0
3 years ago
What is the value for y?<br><br><br><br> Enter your answer in the box.
Anna007 [38]

Answer:

y = 28

Step-by-step explanation:

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x - 5 = 34

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if the two angles 34 + 34 = 68

Then the third angle is 180 - 68 = 112°

4y = 112

y = 28

4 0
3 years ago
Giving Brainliest No Links
AleksAgata [21]

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4 0
2 years ago
Read 2 more answers
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
3 years ago
Jose and Maris work for different car dealerships. Jose earns a monthly salary of $3,500 plus a 6% commission on his sales, x. M
aev [14]

Answer: d.3,500 + 0.06x > 4,000 + 0.04x

Step-by-step explanation:

Hi, to answer this question we have to write each inequality:

Jose earns a monthly salary of $3,500 plus a 6% commission on his sales, x.

So, his monthly earnings must be equal to the sum of the fixed monthly salary ($3500) plus the product of the number of sales (x) and the commission percentage in decimal form (divided by 100):

So:

Jose’s earnings: 3,500 + x (6/100)

Jose’s earnings: 3,500 + 0.06x

Maris earns a monthly salary of $4,000 plus a 4% commission on her sales.

So, her monthly earnings must be equal to the sum of the fixed monthly salary ($4000) plus the product of the number of sales (x) and the commission percentage in decimal form (divided by 100):

Maris’ earnings: 4000+ x (4/100)

Maris’ earnings: 4000+ 0.04 x

Since Jose's earnings must be greater than Maris' earnings

3,500 + 0.06x >4000+ 0.04 x

4 0
3 years ago
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