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Alexxandr [17]
2 years ago
14

Graph the line: y=2/3x-4​

Mathematics
2 answers:
Likurg_2 [28]2 years ago
5 0
Graph the line using the slope and y-intercept, or two points.
Slope:
2
3
2
3
y-intercept:
(
0
,
−
4
)
(
0
,
-
4
)
x
y
0
−
4
3
−
2
kompoz [17]2 years ago
5 0

slope: -\frac{3}{2}

y-intercept: (0, -4) (answer let me know if i am wrong)

Y=2/3x-4 is in Slope - intercept form meaning you are shown the slope (how steep the line is) and the y intercept (where the equation hits the vertical axis)

With the given information, select the point (0, -4) on the graph, this is where the line crosses the y axis, as shown through the -4 in the equation.

Next, look at the slope and you'll see 2/3x. Slope is in format "rise over run" meaning the first number (2) is the vertical change, so up two, and the second number (3) is horizontal change, right 3.

Combine these two steps together and select point (0. -4) then the next point should be at (3,2), 2 units up and three to the right from the y intercept.

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Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

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x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121

Add 10x to both sides:

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Add  (\frac{20}{2})^2=10^2  inside the parentheses of "y".

Add 5^2 and 10^2 to the right side of the equation.

Then:

(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4

Rewriting, you get that the equation of the circle in center-radius form is:

 (x+5)^2+(y-10)^2=2^2

You can observe that the radius of the circle is:

r=2

And the center is:

(h,k)=(-5,10)

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