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3 years ago

If point P(2,-4) is reflected over the y-axis, determine the coordinates the image.

Mathematics

1 answer:

Katen [24]3 years ago

4 0

Point P wold end up being ( -2,-4)

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Simplify 12(x-4)+4(x+7)

My name is Ann [436]

Expand

12x - 48 + 4x + 28

Collect like terms

(12x + 4x) + (-48 + 28)

Simplify

16x - 20

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3 years ago

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If side AB is parallel to side DC, how are side A'B' and side D'C' related? Explain.

anastassius [24]

Side A’B’ and D’C’ are related because they are both parallel which I think means that they would be the same length

7 0

3 years ago

ace wants to buy clothes for his birthday. He has $40. He purchase a white shirt for $14. He spends the rest of his money on bla

anygoal [31]

Answer:

14+ 8n<40

Hope this helps

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3 years ago

Work out the surface area of a cylinder when the height = 18cm and the volume = 1715cm cubed

lara [203]

Answer:

813.4 cm² (nearest tenth)

Step-by-step explanation:

Volume of a cylinder

$\sf V=\pi r^2 h \quad\textsf{(where r is the radius and h is the height)}$

Given:

h = 18cm
V = 1715 cm³

Use the Volume of a Cylinder formula and the given values to find the radius of the cylinder:

$\implies \sf 1715=\pi r^2 (18)$

$\implies \sf r^2=\dfrac{1715}{18 \pi}$

$\implies \sf r=\sqrt{\dfrac{1715}{18 \pi}$

Surface Area of a Cylinder

$\sf SA=2 \pi r^2 + 2 \pi r h \quad\textsf{(where r is the radius and h is the height)}$

Substitute the given value of h and the found value of r into the formula and solve for SA:

$\implies \sf SA=2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)^2 + 2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)(18)$

$\implies \sf SA=2 \pi \left(\dfrac{1715}{18 \pi} \right) + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)$

$\implies \sf SA=\dfrac{1715}{9} + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)$

$\implies \sf SA=813.3908956...$

Therefore, the surface area of the cylinder is 813.4 cm² (nearest tenth)

8 0

2 years ago

Read 2 more answers

Solve for points. identify the vertex and indicate whether it is max or min.

Keith_Richards [23]

Answer:

min at (3, 0 )

Step-by-step explanation:

given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

y = (x - 3)² = x² - 6x + 9 ← in standard form

with a = 1 and b = - 6 , then

$x_{vertex}$ = - $\frac{-6}{2}$ = 3

substitute x = 3 into the equation for corresponding value of y

y = (3 - 3)² = 0² = 0

vertex = (3, 0 )

• if a > 0 then vertex is minimum

• if a < 0 then vertex is maximum

here a = 1 > 0 then (3, 0 ) is a minimum

4 0

2 years ago