Answer:
A) (-8, -16)
B) (0, 48)
C) (-4, 0), (-12, 0)
Step-by-step explanation:
A) the vertex is the minimum y value.
extremes of a function we get by using the first derivation and solving it for y' = 0.
y = x² + 16x + 48
y' = 2x + 16 = 0
2x = -16
x = -8
so, the vertex is at x=-8.
the y value is (-8)² + 16(-8) + 48 = 64 - 128 + 48 = -16
B) is totally simple. it is f(0) or x=0. so, y is 48.
C) is the solution of the equation for y = 0.
the solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac)) / (2a)
in our case here
a=1
b=16
c=48
x = (-16 ± sqrt(16² - 4×48)) / 2 = (-16 ± sqrt(256-192)) / 2 =
= (-16 ± sqrt(64)) / 2 = (-16 ± 8) / 2 = (-8 ± 4)
x1 = -8 + 4 = -4
x2 = -8 - 4 = -12
so the x- intercepts are (-4, 0), (-12, 0)
The answer is d. 39.
Rectangle: 6*3 = 18
Big Triangle: (5*6)/2 = 15
Smaller Triangle: (4*3)/2 = 6
18+15+6=39.
Hope this helped☺☺
Answer:
x=12
Step-by-step explanation:
82 +70= 152
180-152=28
2(12)+4= 28
boom there is your answer
Answer:
B. Sometimes true
Step-by-step explanation:
The answer will be sometimes true because it can be true or false.
The median will be changed if the maximum value of the data set replaced into a value that smaller than the median. Let say we have data of 1, 2, 3, 4, 5 then the median is 3 and the maximum value is 5. If we change the maximum value into 3 or 4, the data set will still have 3 as the median. In this case, the median is not changed thus it's false.
But if we change the maximum value into 2, the data set will become 1, 2, 2, 3, 4. In this case, the median changed into 2 thus it's true.
ANSWER
The correct answer is B
<u>EXPLANATION</u>
The first function is
We make y the subject to obtain;
Let us quickly write this in the vertex form.
Since the 
is negative, the graph opens up.
The vertex is at 
The y-intercept is 
The x-intercept is found by equating the function to zero.
With these information we can quickly sketch the graph as shown in the attachment(the red graph).
For the second function,
we again make y the subject to obtain,
This is a basic quadratic function that can be graphed easily. Note that it is also a maximum graph.
From the graph the solution to the two functions is
