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Novay_Z [31]
3 years ago
7

Consider the linear function that is represented by the equation y = 2 x + 2 and the linear function that is represented by the

graph below.
On a coordinate plane, a line goes through points (negative 1, negative 1) and (0, 1).

Which statement is correct regarding their slopes and y-intercepts?
The function that is represented by the equation has a steeper slope and a greater y-intercept.
The function that is represented by the equation has a steeper slope, and the function that is represented by the graph has a greater y-intercept.
The function that is represented by the graph has a steeper slope, and the function that is represented by the equation has a greater y-intercept.
The function that is represented by the graph has a steeper slope and a greater y-intercept.
Mathematics
1 answer:
lana [24]3 years ago
7 0

Answer:

Answer: I believe the answer is C: The function that is represented by the graph has a steeper slope, and the function that is represented by the equation has a greater y-intercept.

Step-by-step explanation: The Y intercept of the equation is 2 and when I put the 2 graphs side by side the graphs slope looks steeper

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a 9 grade math class has 27 students there are twice as many girls in this class as there are boys.write a system of equation th
Leona [35]
If there are x boys, there are 2x girls. boys+girls=27 gives x+2x=27. Solving, 3x=27 or x=9. Since there are 2x girls, there are 2*9=19 girls.
4 0
3 years ago
If x-25=11, what is the value x/6
ladessa [460]

Question: If <u>x-25 = 11</u>, then what is the solution of x/6?

Step-by-Step Explanation:

1. 25 + 11 = 36

2. x = 36

3. 35/6 = 6

5 0
3 years ago
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5 years ago, Cheryl was d years old, Brandon is 2 years older than Cheryl.
lana [24]

Answer: See explanation

Step-by-step explanation:

a. how old is Cheryl?

Cheryl's age = d + 5

b. how old is Brandon?

d + 5 + 2

= d + 7

c. what was the difference in their ages 5 years ago?

Cheryl age five years ago = d

Brandon's age five years ago = d + 2

Difference = d + 2 - d = 2 years

d. what is the sum of their ages now?

Cheryl's age = d + 5

Brandon age = d + 7

Sum = d + 5 + d + 7

= 2d + 12

e. what will the sum of their ages be two years from now?

Two years from now,

Cheryl's age = d + 5 + 2 = d + 7

Brandon age = d + 7 + 2 = d + 9

Sum = d + 7 + d + 9

= 2d + 16

f. what will the difference of their ages be two years from now

Two years from now,

Cheryl's age = d + 5 + 2 = d + 7

Brandon age = d + 7 + 2 = d + 9

Difference = Brandon age - Cheryl age

= (d + 9) - (d + 7)

= 2 years.

4 0
3 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
A pack of 24 cans costs £6. Work out the cost of 5 cans.
VARVARA [1.3K]
<span>24 cans costs £6

6/24 = 0.25 each can

5 * 0.25 = </span><span>£1.25

answer: </span>£1.25 for <span>5 cans</span>
6 0
3 years ago
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