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OverLord2011 [107]
3 years ago
10

Juan decided to start saving for college. He deposited $500 into an account which earns 4% simple annual interest. At the end of

each year, he will add $250 to this account. How much will he have in his account after the end of three years?
Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

$5504

Step-by-step explanation:

Given that :

Principal amount = $500

Interest = 4% simple interest annually

Amount added at the end of each year :

First year:

Principal + (Principal * rate * time)

500 + (500 * 0.04) = 520

$520 + $250 = $770

2nd year:

770 + (770 * 0.04) = $800.80

$800.80 + $250 = 1050.80

3rd year:

1050.8 + (1050.8 * 4) = 5254

$5254 + 250 = $5504

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The population of coyotes in the northwestern portion of Alabama is given by the formula p (t )equals (t squared plus 100 )ln (t
elena-14-01-66 [18.8K]

Answer:

The rate of change of the Coyote population in 2002 is 32

Step-by-step explanation:

Given the formula for the population of a Coyotes in the Northwestern portion of Alabama, we are to calculate rate of change of the Coyote population in the year 2002 where t = 2

The formula is given as;

P(t) = (t^2 + 100) ln (t + 2)

The rate of change refers to the first integral of the formula;

Thus we need to calculate this by the use of product formula;

The first differential of t^2 + 100 is 2t

while that of ln(t + 2) is 1/(t + 2)

P’(t) = 2t(ln (t+2)) + (t^2 + 100) (1/t+2)

Now, we substitute 2 for the value of t here.

P’(2) = 2(2)( ln (2 + 2) + (2^2 + 100)(1/(2+2))

P’(2) = 4 ln 4 + 104(1/4)

P’(2) = 4ln 4 + 26

P’(2) = 5.55 + 26 = 31.55 which is approximately 32

8 0
3 years ago
PLEASE HELP ANSWER THESE QUESTIONS!
Sliva [168]

Answer:

Step-by-step explanation:

a² - b² = (a+ b)(a - b)

1) (2n-4/2n) ÷ (n^2-4/n)

=\frac{2n-4}{2n}*\frac{n}{n^{2}-4}\\\\=\frac{2n-2*2}{2n}*\frac{n}{n^{2}-2^{2}}\\\\=\frac{2*(n-2)}{2n}*\frac{n}{(n+2)*(n-2)}\\\\=\frac{1}{n+2}

2) [y^2-36/y^2-49] ÷[ y+6/y-7]

=\frac{y^{2}-36}{y^{2}-49}*\frac{y-7}{y+6}\\\\=\frac{y^{2}-6^{2}}{y^{2}-7^{2}}*\frac{y-7}{y+6}\\\\=\frac{(y+6)*(y-6)}{(y+7)*(y-7)}*\frac{y-7}{y+6}\\\\=\frac{y-6}{y+7}\\

3) [m^2-1/ m^2-m] ÷ [m^2-7m-8/3m ]

=\frac{m^{2}-1}{m^{2}-m}*\frac{3m}{m^{2}-7m-8}\\\\=\frac{(m+1)*(m-1)}{m*(m-1)}*\frac{3m}{(m-8)*(m+1)}\\\\=\frac{3}{m-8}

Hint :  m² - 7m - 8

sum = -7

Product  = -8

Factor = (-8), 1

m² - 7m - 8  =m² - 8m + m - 8

                   = m*(m - 8) + (m-8)

                   = (m - 8)(m +1)

7 0
3 years ago
Factiorize; y*2-4,is the question​
Viktor [21]

Answer:

(y - 2)(y + 2)

standard factorization!

tadah

4 0
2 years ago
Please help with number 8 just real answers please
Semenov [28]
B because it makes the most sense to me
7 0
3 years ago
a loaded truck is traveling 20 mph faster than a freight train. In the time it takes the train to travel 160 miles, the truck tr
almond37 [142]
Speed of trucks= x speed of trains =x-30 A loaded
6 0
3 years ago
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