Answer:
y = |x| + 3.
Step-by-step explanation:
The movement of the y value from 1 to 4 is a translation of 3 units upwards.
The graph is y = |x| + 3.
9514 1404 393
Answer:
1. the longer frame (B) has the shorter width
2. the shorter width is 6 3/7 inches, area divided by length
Step-by-step explanation:
The relation between area, length, and width is ...
A = LW
Then the width is ...
W = A/L . . . . . inversely proportional to length
__
1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.
__
2. The width of frame B is ...
W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in
Answer:
Slope: 
Y intercept: 7
Equation: 
Step-by-step explanation:
The slope is found by doing the equation 
. When looking at the first two points, it's shown that the rise (difference between the two y values) is -3 (since it decreased by 3) and the run (difference between the two x values) is 4 (since it increased by 4).
This gives us a slope of .
The y intercept is found by looking at the y value when x = 0. In this picture, it is clear that it is 7.
The equation you want to use is y = mx + b , where b is the y intercept and m is the slope. Just plug in the numbers and you got your equation!
Answer:
The correct option is C
Step-by-step explanation:
A: We know that the lower quartile is 144, and the upper quartile is 129.5 is you add them all up it is going to equal 273.3. So we know that A can now be crossed out.
B: We know that the lower quartile is 146, and that means the upper quartile is 136.5. So adding all of these numbers up we ill get 282.5 So now <u>B can be crossed out</u>
C: The lower quartile is 114 and the upper quartile is 129.5 and when we add those two numbers up we are going to get 243.5. So we are going to keep this number
D: For the last one we know the lower quartile is 214 and upper is 129.5, and when we add this we get 343.5. So we can cross this out and<u> the only one we have left is going to be C</u>
<u>Hope this help's</u>
