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4 years ago

Help with number 1!! And also 1 week= 5 days in this exercise okay!

Mathematics

1 answer:

KatRina [158]4 years ago

7 0

Each student collects $1 per week.
There are 24 students, so combined, they collect $24 per week.
The time irt takes to collect $1500 is

$1500/$24 = 62.5

Answer 62.5 weeks, or if you need a whole number, 63 weeks.

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Convert 0.0000001 to a power of 10.

Murljashka [212]

Answer:

0.0000001 (one ten millionth)

Step-by-step explanation:

3 0

3 years ago

Geometry and perimeter help plz :(

Novay_Z [31]

Answer:

11.)4.79mi

12.)8cm

13.)10.6km

14.)5.93

15.)2yd

16.)5.41in

17)2y

18)2m

19)11.8yd

20)4.51km

Step-by-step explanation:

11.)15.8x2=31.6 31.6/6.6=4.79

12.)64/8=8

13.)26x2=54 54/4.9=10.6

14.)8.6x2=17.2 17.2/5.93

15.)2/1=2

16.)29.2/5.4=5.41

17)4/2=2

18)10/5=2

19)139.2/11.8=11.8

20)20.3/4.5=4.51

3 0

3 years ago

1,3,1,12,1,48,1 use the pattern to find next number

charle [14.2K]

Multiplying by 4 so 48 times 4 is 192

6 0

3 years ago

Prove algebraically that the recurring decimal 0.72 =8/11

miskamm [114]

Answer:

see explanation

Step-by-step explanation:

We require 2 equations with the recurring decimal placed after the decimal point.

let x = 0.7272.... (1) ← multiply both sides by 100

100x = 72.7272... (2)

Subtract (1) from (2) thus eliminating the recurring decimal

99x = 72 ( divide both sides by 99 )

x = $\frac{72}{99}$ = $\frac{8}{11}$

7 0

3 years ago

Read 2 more answers

A dog weighs two pounds less than three times the weight of a cat. The dog also weights twenty-two more pounds than the cat. Wri

8090 [49]

Answer:

Weight of dog: 34 pounds,

Weight of cat: 12 pounds.

Step-by-step explanation:

Let d represent weight of dog and c represent weight of cat.

We have been given that a dog weighs two pounds less than three times the weight of a cat.

3 times weight of cat: $3c$

We can represent the given information in an equation as:

$d=3c-2...(1)$

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

$d=c+22...(2)$

Equate both equations:

$3c-2=c+22$

$3c-c-2=c-c+22$

$2c-2=22$

$2c-2+2=22+2$

$2c=24$

$\frac{2c}{2}=\frac{24}{2}$

$c=12$

Therefore, the weight of cat is 12 pounds.

Substitute $c=12$ in equation (2)

$d=c+22$

$d=12+22$

$d=34$

Therefore, the weight of dog is 34 pounds.

4 0

4 years ago