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Anuta_ua [19.1K]
3 years ago
8

Help plssssssssss omgggg

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

  5\dfrac{7}{8} c +7

Step-by-step explanation:

The like terms are the ones containing the variable 'c'. They are combined by adding their coefficients.

Working just with the coefficients of c, we have ...

  2\dfrac{3}{4} +3\dfrac{1}{8}=(2+3)+\left(\dfrac{6}{8}+\dfrac{1}{8}\right)=5\dfrac{7}{8}

Then the simplified expression is ...

  (2 3/4)c +(3 1/8)c +7

  = (5 7/8)c +7

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A value is in the domain if there is a ____ on the graph of the function at that x-value
fredd [130]
<span>A value is in the domain if there is a point on the graph of the function at that x-value</span>
5 0
3 years ago
For each value y what is a solution to 5y-1&gt;24
emmasim [6.3K]

Answer:

y = 5

steps:

1). Move all terms not containing y to the right side of the inequality.

5y>25

2). Divide each term by 5 and simplify.

y>5



3 0
3 years ago
Helppppppp math !!!!!!!!!!
zhannawk [14.2K]

We conclude that the profit if the company produces 10 units is 1,040 dollars.

<h3></h3><h3>How to find the profit?</h3>

The profit is defined as the difference between the revenue and the costs.

In this case, we know that the revenue and costs are defined by:

R(x) = 200x - 5x^2

C(x) = 360 + 6x

Then the profit equation is:

P(x) = R(x) - C(x).

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P(x) = -5x^2 + 194x - 360

Now we want to find the profit when x = 10, then we will get:

p(10) = -5*10^2 + 194*10 - 360 = 1,040

We conclude that the profit if the company produces 10 units is 1,040 dollars.

If you want to learn more about profit:

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5 0
2 years ago
max picks two different cards without replacement from a standard $52$-card deck. what is the probability that the cards are of
nikdorinn [45]

The probability that cards are from different suits is \frac{39}{51}

Probability of an event E represented by P(E) can be defined as (The number of favorable outcomes )/(Total number of outcomes).

There are 4 suits hearts, diamonds, club and spade in a standard deck of 52 cards.

Each of them has 13 cards each .

So when we pick first card from a single suit

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We can pick the 2nd card from the same suit in 12 different ways .

So to pick 2 cards from a single suit we have 13x12 ways.

to pick 2 card from 4 suits = 4x13x12=624 ways

Total ways of choosing 2 cards from the pack of 52 cards is 52 X 51 =2652

probability that the cards are of same suits=\frac{624}{2652} =\frac{12}{51}

probability that the cards are of different suits=1-\frac{12}{51} =\frac{39}{51}

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3 0
2 years ago
B can you help me ...​
Gemiola [76]
Answer: a is an element of set A. But p is not an element of set A.

Explanation:
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