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Anuta_ua [19.1K]
3 years ago
8

Help plssssssssss omgggg

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

  5\dfrac{7}{8} c +7

Step-by-step explanation:

The like terms are the ones containing the variable 'c'. They are combined by adding their coefficients.

Working just with the coefficients of c, we have ...

  2\dfrac{3}{4} +3\dfrac{1}{8}=(2+3)+\left(\dfrac{6}{8}+\dfrac{1}{8}\right)=5\dfrac{7}{8}

Then the simplified expression is ...

  (2 3/4)c +(3 1/8)c +7

  = (5 7/8)c +7

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Given: ∠T ≅ ∠V; ST || UV
Novay_Z [31]

The respective missing proofs are; Alternate interior; Transitive property; Converse alternate interior angles theore

<h3>How to complete two column proof?</h3>

We are given that;

∠T ≅ ∠V and ST || UV

From images seen online, the first missing proof is Alternate Interior angles because they are formed when a transversal intersects two coplanar lines.

The second missing proof is Transitive property because angles are congruent to the same angle.

The last missing proof is  Converse alternate interior angles theorem

because two lines are intersected by a transversal forming congruent alternate interior angles, then the lines are parallel.

Read more about Two Column Proof at; brainly.com/question/1788884

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7 0
2 years ago
Please help!!!!!!<br><br><br> I will literally award brainliest.<br> I swear cross my heart
kramer
Ummmm I don’t really get it
7 0
3 years ago
Read 2 more answers
A, B, and C are collinear. True or False?
Dafna1 [17]

Answer:

It is false. Just look at the face of the shape.

Step-by-step explanation:

4 0
3 years ago
Find the domain of ( (a+b/b) − (a/a+b))÷( (a+b/a) − (b/a+b) )
Alexandra [31]

Answer:

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, a=-b

Step-by-step explanation:

The domain refers to values for which the expression is defined.

This implies that, the denominators are not equal to zero.

(\frac{a + b}{b} -  \frac{a}{a + b}) \div ( \frac{a + b}{a} -  \frac{b}{a + b})

(\frac{(a + b)(a + b)-ab}{b(a + b)})\div(\frac{(a + b)(a + b)-ab}{a(a + b)})

\frac{(a + b)(a + b)-ab}{b(a + b)} \times\frac{a(a + b)}{(a + b)(a + b)-ab}

\implies \frac{a}{b}

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, and a=-b

7 0
3 years ago
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Can anyone answer this question please<br> 6[y-2]/7-12=2[y-7]/3
Kaylis [27]

Answer:

y =47.5.

Step-by-step explanation:

First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:

21* 6[y-2]/7-21*12 = 21*2[y-7]/3

18(y - 2) - 252 = 14(y - 7)

18y -36 - 252 = 14y - 98

18y - 14y = -98 + 36 + 252

4y = 190

y = 190/4

y = 47.5.

8 0
2 years ago
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