Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer: x = (-50)/3
Answer:
theres nothing there
Step-by-step explanation:
Answer:
Hi there!
Your answer is:
-1 >=x>5
This can be broken down to:
x <= -1
x>5
Which fits your requirements!
Find the Greatest Common Factorthe largest number that divides evenly into <span>4x<span>4x</span></span> and <span>-6<span>−6</span></span>?
It is <span>22</span>.
the highest degree of <span>xx</span> that divides evenly into <span>4x<span>4x</span></span> and <span>-6<span>−6</span></span>?
It is 1, since <span>xx</span> is not in every term.Multiplying the results above,
The GCF is <span>22</span>.
<span><span>2(<span><span>2</span><span><span>4x</span></span><span></span></span>−<span><span>2</span><span>6</span><span></span></span>)
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<span>−2(2x−3)</span>
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