2 years ago

Write an algebraic inequality for the problem, then solve it to

Mathematics

1 answer:

Talja [164]2 years ago

4 0

Answer:

Step-by-step explanation:yes beach iiii∑ω↔↑

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Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

2 years ago

I need to find the angle of a sector of a circle when the arc length is 9pi/8 and the radius is 4.5, please help me!!

Sloan [31]

Answer:

Step-by-step explanation:

jr bacon cheese burger

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2 years ago

The number of students in a school increased by 25%between last year and this year. Last year there were 250 students in the sch

Ber [7]

I believe that is 275 because percent is just out of one hundred

8 0

2 years ago

4. The sum of iwo numbers is 36. Twice the first

Ludmilka [50]

Answer:

14 and 22

Step-by-step explanation:

If x is the first number, then 36-x is the second. We are told that ...

2x -(36-x) = 6 . . . . twice the first less the second is 6

3x = 42 . . . . . . . . . add 36

x = 14

(36 -x) = 22

The numbers are 14 and 22.

4 0

3 years ago

I need help FAST!!! 10pts

Katena32 [7]

The answer is 0.7 kilometers

5 0

3 years ago

Read 2 more answers