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Ray Of Light [21]
3 years ago
10

Write an algebraic inequality for the problem, then solve it to

Mathematics
1 answer:
Talja [164]3 years ago
4 0

Answer:

No

Step-by-step explanation:yes beach iiii∑ω↔↑

You might be interested in
20 is 25% of what number
borishaifa [10]
Hey there! :D

If 20 is 25% of a number, 

we know that it is a quarter of a number. 

20*4= 80

20 is 25% of 80.

I hope this helps!
~kaikers
5 0
3 years ago
Read 2 more answers
In a list of five consecutive odd integers, the sum of the first and double the last is 139. What is the largest sum?
Leviafan [203]

Answer: 49

Step-by-step explanation:

From your question, I think you mean the largest number. The answer is given below.

Let the five consecutive odd numbers be:

a, a+2, a+4, a+6 and a+8.

Thee sum of the first and double the last is 139. This can be written as:

a + 2(a+8) = 139

a + 2a + 16 = 139

3a + 16 = 139

3a = 139 - 16

3a = 123

a = 123/3

a = 41

The first number = 41

The largest number = a+8 = 41 + 8 = 49.

7 0
3 years ago
The waiting time to ride a roller coaster is 20 minutes when 150 people are in line. How long is the waiting time when 240 peopl
laiz [17]

Answer: The waiting time will be 32 minutes when 240 people in line.

Step-by-step explanation:

Let us assume that the waiting time is directly proportional to the number of people in the queue.

Equation of direct proportion between variables x and y :  \dfrac{x_1}{y_1}=\dfrac{x_2}{y_2}

Put x_1=20,\ y_1=150,\ y_2=150  to find  x_2.

\dfrac{20}{150}=\dfrac{x_2}{240}\\\\\Rightarrow\ x_2=\dfrac{20}{150}\times240\\\\\Rightarrow\ x_2=32

Hence, the waiting time will be 32 minutes when 240 people in line.

3 0
2 years ago
Read 2 more answers
Simplify x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
Artemon [7]

Answer:

2x^2 + 2y^2 + 2z^2

Step-by-step explanation:

x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2

First step is to put all the same ones together

( FYI, xy and yx is the same thing, just like how

2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes

(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +

(z^2 +z^2) + (zx - zx)

2x^2 + 2y^2 + 2z^2

All the others just cancel themselves out, for example, xy-xy

When anything minus themselves it will become 0

7 0
3 years ago
can you transform the square shown below into pieces that when put together form five small equal squares whose total area shall
Sunny_sXe [5.5K]

How about this (see attached image):

Use the four cuts as shown in the image (red lines).

Then assemble 5 equal squares by the numbers: 1 center square and the rest are pieced together using two pieces as shown. All five together add up to the same area as original square because we use all pieces.

The way one gets a hint toward a solution is to see how an area of a square of length 1 can be split into 5 equal square areas:

1^2 = 5\cdot x^2\\x = \frac{\sqrt{5}}{5} = \sqrt{\frac{2^2}{5^2}+\frac{1^2}{5^2}}

which indicates we need to find a a triangle with sides 2 and 1 to get the hypotenuse of the right length. That gave rise to the cut pattern (if you look carefully, there are triangles with those side lengths).

6 0
3 years ago
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