Silicate minerals comprise the most common and abundant mineral group on Earth, silicates.
Gas particles lose their energy during collisions
<em>Acetic acid, HC2H3O2</em>
First, calculate for the molar mass of acetic acid as shown below.
M = 1 + 2(12) + 3(1) + 2(16) = 60 g
Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
P1 = ((4)(1)/60)(100%) = <em>6.67%</em>
<em> Carbon:</em>
P2 = ((2)(12)/60)(100%) = <em>40%</em>
<em>Oxygen</em>
P3 =((2)(16) / 60)(100%) = <em>53.33%</em>
<em>Glucose, C6H12O6</em>
The molar mass of glucose is as calculated below,
6(12) + 12(1) + 6(16) = 180
The percentages of the elements are as follow,
<em> Hydrogen:</em>
P1 = (12/180)(100%) = <em>6.67%</em>
<em>Carbon:</em>
P2 = ((6)(12) / 180)(100%) = <em>40%</em>
<em>Oxygen:</em>
P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>
b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal.
I think the answer is B.
I know the answer cant be A because a lot of metal that is new can be shiny.
C is incorrect because malleable means that it can be permanently bent out of shape ( which metal can be )
D is incorrect because a lot of metal can conduct electricity for example copper and brass can both conduct electricity
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Answer:
The molar mass of the unknown compound is 202.40 g/mol.
Explanation:
Let the molar mass of compound be M.
The depression in freezing point is given by:
where,
= change in boiling point = 0.81 K
=Boiling point of the solution = 3.77°C
T = freezing point of the pure solvent here benzene =5.48°C
= freezing point constant = 5.12°C/m
m = molality =
M = 202.40 g/mol
The molar mass of the unknown compound is 202.40 g/mol.