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Aleksandr-060686 [28]
1 year ago
6

A student is studying a sample of neon in a container with a moveable piston (this means the container can change in size). If t

he sample in the container is initially at a pressure of 759.4 torr when the container has a volume of 97.6 mL, what is the pressure of the gas when the piston is moved so that the volume of the container becomes 146.6 mL? Round your answer to the nearest 0.01 and include units!
Chemistry
1 answer:
Maurinko [17]1 year ago
8 0

The new pressure of the gas would be 505.58 torr

<h3>Boyle's law</h3>

According to Boyle's law, the pressure of a gas is inversely proportional to its volume, provided that the temperature is constant.

This can be mathematically represented as: P1V1 = P2V2

In this case, P1 = 759.4 torr, P2 is what we are looking for, V1 = 97.6 mL, and V2 = 146.6 mL

Hence, P2 = P1V1/V2 = 759.4x97.6/146.6 = 505.58 torr

More on Boyle's law can be found here: brainly.com/question/1437490

#SPJ1

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A copper atom has a mass of 1 06 times 10^-22 g and a penny has a mass of 2.5 g. Use this information to answer the questions be
amm1812

Answer:

Mass of 1 mole of copper is 63.83 g.

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

Explanation:

Mass of 1 copper atom,m = 1.06\times 10^{-22} g

1 mole = 6.022\times 10^{23} atoms

Mass of 1 mole of copper :

= 6.022\times 10^{23} atoms\times 1.06\times 10^{-22} g=63.83 g

Mass of 1 mole of copper = 63.83 g

Mass of copper penny = 2.5 g

Atomic mass of copper = 63.83 g/mol

Moles of copper in 2.5 g of copper penny:

\frac{2.5 g}{63.83 g/mol}=0.03916 mol

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

8 0
3 years ago
A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi
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Answer:

V₁  = 374.71  mL

Explanation:

Given data:

Initial volume of gas= ?

Initial temperature = 22°C

Final temperature = 86°C

Final volume = 456 mL

Solution:

Initial temperature = 22°C (22+273 = 295 k)

Final temperature = 86°C (86+273 = 359 k)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₁  = 456 mL × 295 K / 359 k

V₁  = 134520 mL.K /  359 k

V₁  = 374.71  mL

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K2SO4 (aq) + Ca(NO3)2 (aq) ⇒ 2KNO3 (aq) + CaSO4 (s)

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Answer:

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