Answer:
221.7 K
Explanation:
As, PV = nRT
Hence,
6.5 (14) = 5(0.0821)T
91 = 0.4105 T
91 ÷ 0.4105 = T
221.7 = T
Hence the required temperature is <u>221.7 K (Ans)</u>
Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.
Molecular weight of C4H10 is = 58.1 grams
Moles of butane = given mass/ molar mass
= 2/58.1
= 0.0344 mol
Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:
0.0344 x 6.023 x 10^{23} molecules of butane = 2.07 × 10^22 molecules
of butane
Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:
so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.
Thus the no. of carbon atom is 8.28×10^22.
learn more about butane or moles:
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Answer:
Zinc nitrate gives white ppt. which dissolves in excess ammonium hydroxide and produce a colorless solution whereas lead nitrate gives a chalky white ppt. of lead hydroxide which doesnot dissolve.
Explanation:
Hope this helps :)
Answer:
2 KL + Pb(NO3)2 = 2 KNO3 + PbL2
Explanation:
KL + Pb(NO3)2 = KNO3 + PbL2 is unballanced equation, just balance from there :)
C.
Nuclear fission involves the high energy collision of two atomic nuclei to produce one larger nucleus; this process powers stars.
