<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

Compare the terms.

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

<u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u> (For cubic)

Factor (-2)^3 out.

(-2) • (-2) = 4 | Negative × Negative = Positive.

4 • (-2) = -8 | Negative Multiply Positive = Negative.

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.
Hence,

The answer is - 1 / 8
Answer:
4.80 mm to 2 d.p
Step-by-step explanation:
w = f(r)
f'(r) = (dw/dr) = (0.0218 mm/mm)
So, for a small difference in rainfall of 220 mm, what is the corresponding small difference in width of leaves in the two forests given.
One definition of a derivative or a rate of change is that it is the ratio of very small differences in the dependent variable to very small differences in the independent variable.
Mathematically,
(dw/dr) = (Δw/Δr) for very small Δw and Δr.
0.0218 = (Δw/220)
Δw = 0.0218 × 220 = 4.796 mm = 4.80 mm to 2 d.p
Hope this Helps!!!
I'm not sure, but what I got was -8.5, since it is only stating that it is -17 and 5, and you need to figure out Point B, when it is between A and 0. So, you don't pay attention to 1-5. You only want -17 through 0. -17 divided by two would be -8.5
(3x-2)(9x²+6x+4) I think that's it
The answer to your question is 0