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UNO [17]
3 years ago
10

Jay works at a sandwich shop. He needs to make 7 turkey sandwiches. Each sandwich will have 1/3 of a pound of turkey. How many p

ounds of turkey will Jay need to make the sandwiches? Remember what of means! And remember to press submit after you answer the question
Mathematics
2 answers:
disa [49]3 years ago
7 0

Answer:

Jay will need 2 and 1/3 pounds of turkey.

Step-by-step explanation:

Since Jay uses 1/3 per sandwich and is making 7, multiply 7 by 1/3.

That gets you 7/3s

Convert it into a mixed number.

3 goes into 7 twice, with one third left over.

So, Jay needs 2 1/3.

hope this helped!

nikitadnepr [17]3 years ago
4 0

Answer:

approximately 2.3 pounds of turkey. Trust the BlueDragon

Step-by-step explanation:

7 times 1/3= 2.33333

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Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
40 POINTS AND BRAINLIEST!! I NEED THIS DONE ASAP
inna [77]

(a) Answer: One solution.

Explanation: two lines that have same slope with opposite sign will necessarily cross each other at a single point, as one is "pointing uphill" and the other "downhill."

(b)  Answer: Infinitely many solutions.

Explanation:

2x + 3y = 5.5

4x + 6y = 11   | divide by 2

-->

2x + 3y = 5.5

2x + 3y = 5.5

--> equations are identical.

2x + 3y = 2x + 3y

so any (x,y) will satisfy this equation. This means infinitely many solutions.

(c) Answer: One solution

Explanation:

Continuing the two lines it becomes obvious they will cross at one point (the solution)

(d) Answer: No solution

Explanation: If the two lines are parallel, they will never cross (by definition of "parallel"). Therefore there will be no solution to the corresponding linear system.


8 0
3 years ago
Describe the graph of y=3/4x-12 as compared to the graph of y=1/x
Eddi Din [679]

Answer:

Parent function is compressed by a factor of 3/4 and shifted to right by 3 units.

Step-by-step explanation:

We are asked to describe the transformation of function y=\frac{3}{4x-12} as compared to the graph of y=\frac{1}{x}.

We can write our transformed function as:

y=\frac{3}{4(x-3)}

y=\frac{3}{4}*\frac{1}{(x-3)}

Now let us compare our transformed function with parent function.

Let us see rules of transformation.  

f(x-a)\rightarrow\text{Graph shifted to the right by a units},

f(x+a)\rightarrow\text{Graph shifted to the left by a units},

Scaling of a function: a*f(x)

If a>1 , so function is stretched vertically.

If 0<a<1 , so function is compressed vertically.

As our parent function is multiplied by a scale factor of 3/4 and 3/4 is less than 1, so our parent function is compressed vertically by a factor of 3/4.

As 3 is being subtracted from x, so our parent function is shifted to right by 3 units or a horizontal shift to right by 3 units.

Therefore, our parent graph is compressed by a factor of 3/4 and shifted to right by 3 units to get our new graph.

5 0
3 years ago
Evaluate the expression if m=4 n=3 and p=2<br> 5m-4n+p=
laila [671]
The answer is 10

The equation would look like
5(4)-4(3)+2
And if you solve it, you’ll get 10 as your answer
8 0
3 years ago
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A restaurant menu has five kinds of soups, seven kinds of main courses, six kinds of desserts, and five kinds of drinks. If a cu
ryzh [129]

Answer: 1050

Step-by-step explanation:

Number of combinations of selecting r things out of n = ^nC_r=\dfrac{n!}{r!(n-r)!}

such that ^nC_1=n

Given: A restaurant menu has 5 kinds of soups, 7kinds of main courses, 6 kinds of desserts, and 5 kinds of drinks.

If a customer randomly selects one item from each of these four categories, then by fundamental counting principle , the number of different outcomes are possible = ^5C_1\times \ ^7C_1\times\ ^6C_1\times\ ^5C_1 =5\times7\times6\times5=1050

hence, total number of outcomes = 1050

3 0
2 years ago
Read 2 more answers
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