Question

A. 92%

Answer 1

$\huge\mathfrak\blue{answer}$

$c) \: 23\%$

Let's figure out how many pieces of candy there is in total:

10 + 12 + 6 = 28

In total, there are 28 pieces of candy.

Let's find the probability that a piece is sour:

$\frac{10}{28} = \frac{5}{14}$

The probability of pulling a sour piece out of the bag is 5/14.

This means that the probability that the candy pulled is not sour is 9/15 (or simplified 3/5)

To find the probability that the first candy picked out is sour AND the second candy picked is not sour we have to multiply the probabilities of both:

$\frac{5}{14} * \frac{3}{5} = 0.229 = 23\%$

$\huge\sf\blue{thank \: you}$

(Brainliest would be appreciated :))