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Svetlanka [38]
3 years ago
10

I. A rhombus is a special type of square. II. A rectangle is a special type of rhombus. III. A trapezoid is a special type of pa

rallelogram. Which of the above statements are true? i only iii only iii only None of the above statements are true.
Mathematics
1 answer:
Kobotan [32]3 years ago
4 0

Answer: I. only

--------------------------------------------------------------------------------------------------------------

Explanation :

II. False. a rectangle is a special type of rhombus since a rhombus has all sides equal, while a rectangle has all angles equal. A rhombus has opposite angles equal, while a rectangle has opposite sides equal.  The diagonals of a rhombus intersect at equal angles, while the diagonals of a rectangle are equal in length.

I.  True. A square is a special case of a rhombus, because it has four equal-length sides and goes above and beyond that to also have four right angles. Every square you see will be a rhombus, but not every rhombus you meet will be a square.

III. False.  Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. A trapezoid can never be a parallelogram. The correct answer is that all trapezoids are quadrilaterals.

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Assume that blood pressure readings are normally distributed with a mean of 124 and a standard deviation of 6.4. If 64 people ar
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Step-by-step explanation:

We have that the mean (m) is equal to 124, the standard deviation (sd) 6.4 and the sample size (n) = 64

They ask us for P (x <126)

For this, the first thing is to calculate z, which is given by the following equation:

z = (x - m) / (sd / (n ^ 1/2))

We have all these values, replacing we have:

z = (126 - 124) / (6.4 / (64 ^ 1/2))

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ryan took 15 minutes to type his 450 - word report. At this rate, how many words could be type in 20 minutes ?
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Read 2 more answers
If you roll two number cubes ,what is the probability of their sum being 9 or higher?
bija089 [108]

Answer:

5/18

Step-by-step explanation:

When two cubes are rolled there are 36 possibilities

Each dice has 6 equally like outcomes so possibilities are

(1,1)  (1,2)          (1,3)          (1,4)         (1,5)         (1,6)

(2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

(3,1)  (3,2)  (3,3)  (3,4)  (3,5)  (3,6)

(4,1)  (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

(5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

(6,1)  (6,2)  (6,3)  (6,4)  (6,5)  (6,6)

Now we look at the pair that has sum equal to 9

(3,6) (4,5) (5,4) (6,3) that has sum of 9

Probability of sum is 9 = \frac{4}{36}

we look at the pairs that has sum greater than 9

(4,6) (5,5)(5,6) (6,4)(6,5)(6,6)

Probability of sum greater than 9 = \frac{6}{36}

Probability of sum 9 or higher = P(sum 9) + P(greater than 9)

= \frac{4}{36}+\frac{6}{36}= \frac{10}{36}=\frac{5}{18}



4 0
3 years ago
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