Answer:
Tommy had 56 cents in start and Loren had 7 cents in start.
Step-by-step explanation:
Let,
x be the money Tommy have.
y be the money Loren have.
According to given statement;
Tommy had 8 times more money than Loren.
x = 8y Eqn 1
Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore
x-14=y+35 Eqn 2
Putting x=8y in Eqn 2

Dividing both sides by 7

Putting y=7 in Eqn 1

Hence,
Tommy had 56 cents in start and Loren had 7 cents in start.
Answer:
Javier's parents set aside $1500 when he was born
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:

In which E is the interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
In this question, we have that:

We have to find P. So




Javier's parents set aside $1500 when he was born
Answer:
n = 18 cycles
Step-by-step explanation:
To know how many times does the current oscillates in the given time, you take into account that the number of oscillation can be calculated by using the following expression:
(1)
f: frequency of the oscillation of the current
t: time = 0.30s
The frequency is the number of cycles per second, that is, f = 60 cycles/s
You replace the values of f and t in the equation (1):

In 0.30s the current oscillates 18 times
K-7.2>2.1.
+7.2 +7.2
------------------
k> 9.3
are you suppose to solve for k?
D = 0.32
d - 8 / 5 = -4d
d - 1.6 = -4d
d + 4d = 1.6
5d = 1.6
d = 0.32
This is an exact question in my math textbook. It should be correct.