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3 years ago

3(x+4)>12 can yall help me fr

Mathematics

2 answers:

Neko [114]3 years ago

8 0

Answer:

x>0

Step-by-step explanation:

djverab [1.8K]3 years ago

8 0

Answer:

x > 0

Step-by-step explanation:

3(x + 4) > 12

Divide both sides by 3

x + 4 > 4

Subtract 4 from both sides

x > 0

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Which segment is not a radius of circle C cq cp rc pq

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The answer could be D- pq. It's not from the center of the circle.

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3 years ago

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Find the circumference. Use 3.14 for n. r = 6 ft C = [?] ft C=Td

Y_Kistochka [10]

In the circumference formula given d is the diameter which is 2 times r ( r is the radius)

R is given as 6 feet, diameter = 2 x 6 = 12 feet.

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2 years ago

Marge purchased bicycle helmets and tire pumps. Each helmet cost $12.00 and each pump cost $8.00. She purchased a total of 18 it

algol [13]

Answer:

Step-by-step explanation:

Let the no. of helmet be x

cost of 1 helmet = $12.00

cost of x helmet = $12.00*x = $12x

Let the no. of tire pumps be y

cost of 1 tire pumps = $8.00

cost of x tire pumps = $8.00*y = $8y

Given that total no. of helmet and pump is 18

thus

x + y = 18

y = 18-x

also given

total money spent is $188

thus

12x+8y = 188

using y = 18 - x

we have

12x + 8(18-x) = 188

=> 12x+ 144 - 8x = 188

=> 4x = 188-144 = 44

=> x = 44/4 = 11

Thus, no of helmet bought by Margo is 11.

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2 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

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I believe it’s 5,193.0315 I’m not to sure

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3 years ago

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