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Rufina [12.5K]
2 years ago
9

Trigonometry Identities help please

Mathematics
1 answer:
AfilCa [17]2 years ago
6 0

\sin(x) =   - \frac{   \sqrt{2} }{2}
\tan(x)  =   -  \frac{ \sqrt{2} }{ \sqrt{2} }
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What transformations were applied to the graph of the parent function y=tan(x) to produce the function graphed below?
xxMikexx [17]

Answer:

It's D.

Step-by-step explanation:

The graph of tan x passes through (0,0)  whereas this graph passes through the point (pi/4 , 0) so it  a horizontal  translation to the right.  We see that the  period is 6 units along the x axis which is  6 * pi/4 = 3 pi/2.

3 0
3 years ago
Read 2 more answers
How do I find the inverse function of this equation
trapecia [35]

Answer:

y=ln(x/(1-x))

Step-by-step explanation:

y=e^x/(1+e^x)

Cross multiply

y(1+e^x)=e^x

Distribute

y+ye^x=e^x

Put anything with x on with side and everything without x on opposing side:

y=e^x-ye^x

Factor right hand side

y=(1-y)e^x

Divide both sides by (1-y)

y/(1-y)=e^x

Use natural log.

ln(y/(1-y))=x

The inverse is

y=ln(x/(1-x))

4 0
3 years ago
Plz help me plz I really need help
Zolol [24]

Step 1: 198 ×\frac{1}{3} = 66, the number of men who left the party

Step 2: 256×\frac{1}{4}= 64, the number of women who left the party

66+64=130

Since 130 is the number of people that left, you would subtract it from the total number of people at the party originally.

198+256=454

454-130=325

So, 325 people are left at the party

3 0
3 years ago
What is the slope of <br> 4-1- -2,3
ale4655 [162]
The formula is for slope is y2-y1/x2-x1 so 3- -1 = 4 and -2 - 4 = -6 so it would be 4/-6
8 0
3 years ago
Which two values of x are roots of the polynomial below?<br> 3x2-3x+1
QveST [7]

Answer:

The roots are

x=\frac{1}{6} [3+ i\sqrt{3}]

x=\frac{1}{6} [3- i\sqrt{3}]

Step-by-step explanation:

we have

3x^2-3x+1

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2-3x+1=0  

so

a=3\\b=-3\\c=1

substitute in the formula

x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}

x=\frac{3\pm\sqrt{-3}} {6}

Remember that

i=\sqrt{-1}

so

x=\frac{1}{6} [3\pm i\sqrt{3}]

The roots are

x=\frac{1}{6} [3+ i\sqrt{3}]

x=\frac{1}{6} [3- i\sqrt{3}]

6 0
2 years ago
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