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2 years ago

Trigonometry Identities help please

Mathematics

1 answer:

AfilCa [17]2 years ago

6 0

$\sin(x) = - \frac{ \sqrt{2} }{2}$
$\tan(x) = - \frac{ \sqrt{2} }{ \sqrt{2} }$

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Complete the proof of the Chinese remainder theorem by showing that the simultaneous solution of a system of linear congruences

Semenov [28]

Answer:

Sorry I don`t know this

Step-by-step explanation:

I wish I could help you with it

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2 years ago

For the month of January in a certain city, 42% of the days are cloudy. Also in the month of January in the same city, 41% o

zalisa [80]

Answer: 0.9762

Step-by-step explanation:

Let A be the event that days are cloudy and B be the event that days are rainy for January month .

Given : The probability that the days are cloudy = $P(A)=0.42$

The probability that the days are cloudy and rainy = $P(A\cap B)=0.41$

Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

$P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.41}{0.42}=0.97619047619\approx0.9762$

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy = 0.9762

7 0

3 years ago

30 POINTS!!

Viefleur [7K]

Answer:

400

Step-by-step explanation:

He makes $4 per shirt ($12-$8). $1600/4 = 400. So he woud need to see at least 400 shirts to break even.

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2 years ago

The blades of a windmill turn on an axis that is 40 feet from the ground. The blades are 15 feet long and complete 3 rotations e

astraxan [27]

Answer:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

$a = 15\ ft\\\\k = 40\ ft$

$y = 15sin(\frac{\pi}{10}t) + 40$

Step-by-step explanation:

In this problem the amplitude of the sinusoidal function is given by the length of the blades.

$a = 15\ ft$

The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:

$k = 40\ ft$

We know that the blades have an angular velocity w = 3 rotations per minute.

One rotation = $2\pi$

1 minute = 60 sec.

So:

$w = \frac{3(2\pi)}{60}\ rad/s$

$w = \frac{\pi}{10}\ rad/s$

Finally:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

$a = 15\ ft\\\\k = 40\ ft$

$y = 15sin(\frac{\pi}{10}t) + 40$

3 0

3 years ago

Read 2 more answers

I don't know what the question is asking.

pshichka [43]

There are different types of parallelograms,and you probably have the notes determining what type it is. So like it could be a square, rectangle, rhombus..

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3 years ago