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solniwko [45]
2 years ago
14

Last one!!!hdbsjsbsjdsnsjsn​

Mathematics
2 answers:
worty [1.4K]2 years ago
4 0

Answer:

9.4

3rd option

The boats are 9.4 units apart.

BaLLatris [955]2 years ago
3 0

Answer:

Option c is correct

Step-by-step explanation:

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>✌</u></em>

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Vitek1552 [10]

Answer:

c i belive

Step-by-step explanation:

bec why not dude it seems to be self explanatory through the explanation

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3 0
3 years ago
Please help me<br><br> ( - 3 ) ( a + x ) , if a + 8, x = - 10
BARSIC [14]

Answer:

6

Step-by-step explanation:

-3 x (8 + [-10]) =

-3 x (8 - 10) =

-3 x -2 =

6

HOpe that helps!

7 0
3 years ago
Read 2 more answers
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Leviafan [203]

Answer:

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Step-by-step explanation:

7 0
2 years ago
How to solve z+2/z-3=5/-3
OLEGan [10]
(z+2)= (z-3)(5/-3)
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5 0
3 years ago
4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail
Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

h^{-1}(x)=\sqrt{\frac{x+1}{3}} ⇒ answer D

Step-by-step explanation:

* <em>Lets explain how to find the inverse of a function</em>

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = f^{-1}(x)

* <em>Lets use these steps to solve the problems</em>

∵ f(x)=\sqrt{x-3}

∵ f(x) = y

∴ y=\sqrt{x-3}

- Exchange x and y

∴ x=\sqrt{y-3}

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by f^{-1}(x)

∴ f^{-1}(x)=x^{2}+3

∵ g(x) = x² + 3

∴ f^{-1}(x)=g(x)

∴ <u><em>The functions are inverses to each other</em></u>

* <em>Now lets find f(g(x))</em>

- To find f(g(x)) substitute x in f(x) by g(x)

∵ f(x)=\sqrt{x-3}

∵ g(x) = x² + 3

∴ f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x

∴ <u><em>f(g(x)) = x</em></u>

∴ The functions are inverses; f(g(x)) = x

* <em>Lets find the inverse of h(x)</em>

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ \frac{x + 1}{3}=y^{2}

- Take √ for both sides

∴ ± \sqrt{\frac{x+1}{3}}=y

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ \sqrt{\frac{x+1}{3}}=y

- replace y by h^{-1}(x)

∴ h^{-1}(x)=\sqrt{\frac{x+1}{3}}

4 0
3 years ago
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