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Marta_Voda [28]
3 years ago
13

{(6,4),(7,−3),(−4,3),(8,−3)}, which point if added would not create a function?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

Step-by-step explanation:

What points were you given to choose from?

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Answer:

The first one. Zareem takes good notes in class to know the lesson better

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Which expression is equivalent to -1/4 x + 1/2?
Anna71 [15]
The expression is given by:

-\frac{1}{4}x+ \frac{1}{2}

So we need to find an equivalent equation for this problem. Then, we will apply some mathematical rules:

Extracting the common factor 1/4, then:

\frac{1}{4}(-x+2})

Or extracting the common factor -1/4, then:

-\frac{1}{4}(x-2})

So, comparing these solutions with the answers about, there is no any answer that matches.


7 0
3 years ago
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Derivative of tan(2x+3) using first principle
kodGreya [7K]
f(x)=\tan(2x+3)

The derivative is given by the limit

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h

You have

\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}

By this identity, you have

\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}

So in the limit you get

\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}
\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}

The first two limits are both 1, and the single term in the last limit approaches 0 as h\to0, so you're left with

f'(x)=\dfrac12\sec^2(2x+3)

which agrees with the result you get from applying the chain rule.
7 0
3 years ago
The sides of an equilateral triangle measure 16 inches. The midpoints of the sides of the triangle are joined to form another eq
Alex Ar [27]

Answer:

  90 inches

Step-by-step explanation:

The perimeter of the inscribed triangle is 1/2 that of the enclosing triangle. So, the total of perimeters is ...

  (3·16 in)(1 +1/2 +1/4 +1/8) = (48 in)(15/8) = 90 inches

5 0
3 years ago
Write an expression for a number that is 5 times greater than 2
ElenaW [278]

Answer:

x = 5x > 2

or just 5x > 2 ya its that

Step-by-step explanation:

4 0
3 years ago
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