Divide. −5 1/3÷2 3/4 −12 5/6 −7 5/12 −1 31/33 −1 11/12

FIRST CORRECT ANSWER WILL GET BRAINLIEST!!!

Mars2501 [29]

Their are 6 equilateral triangles in a regular hexagon:
The area of one triangle = (x²√3)/4, then:
1st answer: The area of the hexagon base: is 6 TIMES the area of one equilateral triangle [or, needed for 2nd, question, TOT AREA:(6x²√3)/4] = (3x²√3)/2] unit²

2nd answer: :
Volume of pyramid: (base area)(height)/3
Volume of pyramid: (3x²√3).(3x)/3 (because height = 3x, given)
Then Volume of pyramid= 3x³√3 unit³.
3 is the answer for the second question
and 6 for the 1st

4 0

3 years ago

A circular picture is 8 inches in diameter.

velikii [3]

The formula of an area of a circle with radius r:

$A=\pi r^2$

Part A.

We have diameter of the circle d = 8 in. The diameter of a circle is equal two times length of a radius.

Therefore:

$r=\dfrac{d}{2}\to r=\dfrac{8}{2}=4\ in$

Calculate the area:

$A=\pi\cdot4^2=16\pi\ in^2$

Answer: C. 16π square inches.

Part 2.

Look at the picture.

Total area:

$A=\pi\cdot6^2=36\pi\ in^2$

Answer: C. 36π square inches

7 0

3 years ago

A prism is completely filled with 1120 cubes that have edge lengths of 1/2 in. What is the volume of the prism?

DedPeter [7]

Answer:

Volume of the prism = 140 cubic inches.

Step-by-step explanation:

The edge length of the cube is 1/2 inches.

The volume of the cube is given by

$\text{Volume}=(\text{edge})^3\\\\V=(1/2)^3\\\\V=0.125$

Now, it has been given that there are 1120 cube is completely filled in the prism. Hence, we have to the multiply the volume by 1120.

Volume of the prism = 1120 × 0.125

Volume of the prism = 140 cubic inches.

6 0

3 years ago

Read 2 more answers

HELP PLEASE!!!

True [87]

Answer:

The graph of f(x) is shifted k units to the right of the graph of g(x).

Step-by-step explanation:

Given the function and where k <0.

As, horizontal depends on the value of x and are when

g(x)=f(x+h) graph shifted to left.

g(x)=f(x-h) graph shifted to right.

Now, given

But here k is negative, when k is considered positive then f(x) becomes

⇒ The graph of f(x) is shifted k units to the right of the graph of g(x).

Correct option is B.

6 0

3 years ago

If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei

MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is ${11 \choose 3} = 165 .$ As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is ${7 \choose 3} = 35$ . Thus, there are only 35 ways to distribute the blackboards in this case.

4 0

3 years ago