From the information given, a right-tailed test using the z-distribution is appropriate.
At the null hypothesis, it is <u>tested if the class of statistics students is not significantly smarter than the general population</u>, that is, their mean IQ is of at most 100, hence:

At the alternative hypothesis, it is <u>tested if they are significantly smarter</u>, that is, their mean IQ is greater than 100, hence:

- We are testing if the mean is <u>greater than a value</u>, hence it is a right-tailed test.
- We have the <u>standard deviation for the population</u>, hence, the z-distribution is used.
A similar problem is given at brainly.com/question/23413408
546464433311\]jbuuuykuyvfutrrtur
Answer:
“The true mean weight of the piglets is at most 39lbs”would be the alternate hypothesis.
Step-by-step explanation:
Given that the null hypothesis of an experiment is “The true mean weight of the piglets is at least 39lbs”
We have to find the alternate hypothesis.
In hypothesis testing, alternate is the opposite of null hypothesis. If null hypothesis supports one statement alternate hypothesis opposes it. In other words, alternate hypothesis would be the negative of the claim of null hypothesis.
Here the null hypothesis of an experiment is “The true mean weight of the piglets is at least 39lbs”
i.e H0: 
So alternate hypothesis
Ha: 
B and C
0+11= +11
0-11= -11
Hope this helps
Answer:
C
Step-by-step explanation:
The ratio 11:16 cannot be simplified