Answer:
B
Step-by-step explanation:
It's b my correct answer is b
The function that represents Wayne´s elevation:
y = 30 x - 105
The function that represents Winston´s elevation:
- 100 = 0 m + b
b = -100
-16 = 3m - 100
3 m = 84
m = 84 : 3 = 28
y = 28 x - 100
Surface level: y = 0
Wayne:
0 = 30 x - 105
x = 3.5 minutes
Winston:
0 = 28 x - 100
x = 3.57 minutes
If they both ascend at the same rate, Wayne will be first to the surface.
Step-by-step explanation:
look at the pic................... hope it helps
Answer:
The distribution is 
Solution:
As per the question:
Total no. of riders = n
Now, suppose the
is the time between the departure of the rider i - 1 and i from the cable car.
where
= independent exponential random variable whose rate is 
The general form is given by:

(a) Now, the time distribution of the last rider is given as the sum total of the time of each rider:


Now, the sum of the exponential random variable with
with rate
is given by:

Hello!
We have two probabilities we can use; we have 170/400, for our experiment, and 1/2, which is our theoretical probability.
To solve, we just multiply the two probabilities.
=0.2125≈21.3
Therefore, we have about a 21.3% chance of this event occurring.
I hope this helps!