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Softa [21]
3 years ago
15

Can someone please help me ASAP

Mathematics
1 answer:
Irina-Kira [14]3 years ago
8 0

Answer:

no se ve bien la foto

tómalo de nuevo

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35 POINTS, PLEASE HELP, I'M TIMED!!! What is the volume of a cylinder that has the following measurements?
iris [78.8K]

Answer:

hope im right!

Step-by-step explanation:

i believe it is 128.6!

3 0
3 years ago
It takes Emmanuel 20 minutes to walk to school. It takes Liah 80% as long to walk to school. How long does it take Liaqh to walk
77julia77 [94]

Answer:

16 minutes

Step-by-step explanation:

80% of 20 is

80/100 * 20 = 16

6 0
3 years ago
What is the volume of a right circular cylinder with a radius of 4 m and a height of 4 m?
CaHeK987 [17]

Answer:

64π m³

Step-by-step explanation:

The general formula for the volume of a cylinder:

V = πr²h, where 'r' is the radius and 'h' is the height

In the given problem, the radius is equal to 4 m and the height is equal to 4 m.  Plugging these values into the equation:

V = π4²(4) = π16*4 = 64π m³

5 0
4 years ago
The two segments formed as a result of a bisector will always be
hjlf

Answer:

two equal parts .

Step-by-step explanation:

The bisector is breaking the attribute or the objects  into the 2 equal parts that are equivalent. The bisector is applied to the segments with the angles and the curves.

  • We can draw the line that divided the into the 2 angle or the two parts the two angle  are of equal angle .
  • The two angle that are of equal is known as bisector angle .  
6 0
3 years ago
Find the distance between A and B.
Papessa [141]

Answer:

The result is d = 2\sqrt{5} units.

Step-by-step explanation:

The coordinates for A and B:

A = (-2, 0)

B = (2, 2)

-To find the distance between A and B, you need the distance formula:

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2}-y_{1})^2} Where the first coordinate is (x_{1},y_{1}) and  the second coordinate is (x_{2}, y_{2}).

-Use the coordinates A and B for the equation:

d = \sqrt{(2+2)^2 + (2-0)^2}

-Then, you solve the equation:

d = \sqrt{(2+2)^2 + (2-0)^2}

d = \sqrt{(4)^2 + (2)^2}

d = \sqrt{16 + 4}

d = \sqrt{20}

d = 2\sqrt{5}

So, therefore the distance is 2\sqrt{5} units.

7 0
4 years ago
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