Your "<span>h (x)=x 2 squared +6x-3" is ambiguous. If you meant "x squared," then you need only write x^2 OR "x squared," but NOT "x 2 squared."
I will assume that by "</span><span>h (x)=x 2 squared +6x-3" you actually meant:
</span><span>h(x)=x^2 +6x-3. To find h(3), subst. 3 for x: h(3) = (3)^2 + 6(3) - 3, or
h(3) = 9 + 18 - 3, or h(3) = 24.</span>
Answer:
x=1
Step-by-step explanation:
Look at the bottom of the triangle you will see that 1 = x
Answer:
16. d = distance
r = rate
t = time.
We know that the rate = 4, and time = 11.
=> d = 4 * 11
=> d = 44
17. We know that distance = 36, and time = 4.
=> 36 * r* 4
=> 36 = 4r
=> 36/4 = 4r/4
=> r = 9
(1/4)^-2 - (5^0 x 2) x 1^-1 =
(4/1)^2 - (1 x 2) x 1 = 16-2 = 14
If you raise something to the power of -2, swap numerator and denominator and remove the minus.
So (1/4)^-2 = 4^2 = 16
Also 1^-1 is just 1, not -1.
