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3 years ago

13

I need help with number 1 please

1 answer:

notka56 [123]3 years ago

8 0

Conquered the Macedonian Satrapies and won the Seleucid-Mauryan war.

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If 6^4x = 82, what is the value of x?<br> Round your answer to three places.

neonofarm [45]

Answer:

$x=0.61485921$

Step-by-step explanation:

The given equation is in exponential form:

$6^{4x} =82$

To find $x$ we need to write it in logarithmic form:

$b^{a} =n$ ⇒ $log_{b} n=a$

$6^{4x} =82$ ⇒ $log_{ 6 } 82=4x$

$2.45943684 = 4x$

$\frac{2.45943684}{4} = x$

$0.61485921 =x$

To prove this, we can substitute the value into the given equation

$6^{4x} =82$

$6^{4(0.61485921)} =82$

$82=82$

Therefore, the answer is $x=0.61485921$

6 0

3 years ago

PLZ HURRY Solve for g.<br><br>g3 – 1 > 2

Phoenix [80]

$g3 - 1 > 2$

$g3 - 1 + 1 > 2 + 1$

$g3 > 3$

$\frac{g3}{3} > \frac{3}{3}$

$g > 1$

//

If the 3 is an exponent, then the person above me is right.

5 0

3 years ago

Solve for g please!!!!!!!!!!!!!!

alexandr402 [8]

G = m/5t- Q^2. Hope that helps.

4 0

3 years ago

Which would be an equivalent way to write y= 2 - 3x ?

Fudgin [204]

The answer is B, because the numbers in the equation are 2, and -3x. The signs have to stay with the numbers they are with. So if you move the 3 to the front you have to keep the negative with it.

6 0

3 years ago

Express the radical using the imaginary unit i

valentinak56 [21]

Answer:

$=\pm i\sqrt{66}$

Step-by-step explanation:

So we have:

$\pm\sqrt{-66}$

This is the same as:

$=\pm\sqrt{66\cdot-1}$

Separate:

$=\pm\sqrt{66}\cdot\sqrt{-1}$

Replace the second term with i:

$=\pm i\sqrt{66}$

The square root of 66 cannot be simplified.

So, this is our answer :)

7 0

3 years ago