Answer:
$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Normally distributed with mean $480 and standard deviation $20.
This means that 
How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05?
This is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95, so X when Z = 1.645.




$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05
Answer:
= 3.1415926...= c/d
Step-by-step explanation
Pie is infinite so there is no simple answer.
circumference divided by the diameter = pie
Answer:
See below
Step-by-step explanation:
Let P(x) be a predicate over the variable x. Rules from logic tell us that the negation of ∀xP(x) is ∃x(¬P(x)). That is, the negation operator ¬ satisfies ¬(∀xP(x))≡∃x(¬P(x)). Similarly, ¬(∃xP(x))≡∀x(¬P(x)).
Apply these rules to each statement to obtain:
a) ∃ a fish x, x does not have gills.
b) ∃ a computer c, c does not have a CPU.
c) ∀ movie m, m is not over 6 hours long. ⇔ ∀ movie m, m is under 6 hours long.
d) ∀ band b, b has not won at least 10 Grammy awards. ⇔ ∀ band b, b has won less than 9 Grammy awards.
Y = -x + 4
y = 3x + 3
3x + 3 = -x + 4
3x + x = 4 - 3
4x = 1
x = 1/4
y = 3x + 3
y = 3(1/4) + 3
y = 3/4 + 3
y = 3/4 + 12/4
y = 15/4
solution is (1/4,15/4)
so line y = -x + 4 intersects the line y = 3x + 3 at (1/4,15/4)