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Diano4ka-milaya [45]
3 years ago
5

Solo necesito ayuda con las que están en amarillo las otras ya están realizadas

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0
Solo tienes que divide
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Simplify 3.7x+(0.5-6y)+0.8-(1.7x+1-2.3y)
hammer [34]

Answer:

2x-3.7y+0.3

Simplify the expression.

Step-by-step explanation:

6 0
3 years ago
2. JENNIFER IS TRYING TO SAVE MONEY. SHE WILL TAKE $150.00 TO
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Hope this helps.

If not, go to: https://www.mathportal.org/calculators/financial-calculators/simple-interest-calculator.php

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3 years ago
0.611111111. .. repeating equals<br> Q. 12/19<br> b. 11/18<br> c. 13/20<br> d. 10/17
-Dominant- [34]

Answer:

B. 11/18

Step-by-step explanation:

Solve using algebra.

x = 0.611111...

10x = 6.111111...

10x - x = 6.111111.. - 0.61111111..

9x = 5.5

x = 5.5/9

x = 11/18

7 0
3 years ago
I need help with this math problem please
Gekata [30.6K]

Answer:

C)  3(x+7)²

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose you choose a marble from a bag containing 3 red marbles, 5 white marbles, and 4 blue marbles. You return the first marbl
Veseljchak [2.6K]

Answer:

P(red and blue) = 0.1667

Step-by-step explanation:

Let A represent choosing a red marble, there are 3 red marbles

Let B represent choosing a blue marble, there are 4 blue marbles

There are 12 total marbles

Then...

P(A) = 3/12

P(B) = 4/12

choosing the first one, then replacing means the first choice has no effect on the probabilities of the second choice, so the situation is independent.  

When calculating the probability of independent events, you multiply the probabilities together.  There are 2 scenarios where we can get a red and blue marble..

Choosing a red, then a blue marble, the probability is

(3/12)( 4/12) = 12/144 = 1/12

Choosing a blue, then a red marble, the probability is

(4/12)(3/12) = 12/144 = 1/12

So we have a

(1/12) + (1/12) = 2/12 = 1/6 chance for that to happen, to

P(A and B) = 1/6 = 0.1667

6 0
3 years ago
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