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dimulka [17.4K]
2 years ago
6

PLS HELP

Mathematics
1 answer:
NARA [144]2 years ago
4 0

Answer:

1) w = 9

2) h = 3.83

3) x = -60

4) x = 13/9

5) x = 2.64

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4y+12=0<br> How do I get the two points to be graphed
coldgirl [10]

Did somebody say you're supposed to draw the graph of the equation ?
Is that the assignment ?

OK.  Just like every other equation you need to graph, get it in the
standard form, where 'y' is all alone on one side, and everything else
is on the other side.  When you do that, you'll be able to spot the slope
and y-intercept of the  line, or get some points, or whatever you want.

                                               4y + 12  =  0

Subtract 12 from each side:          4y  =  -12

Divide each side by 4:                      y  =  -3

There's the equation you can handle. 
The y-intercept is -3, and the slope is zero.

Would you like some points ?  OK.  Pick a couple of values for 'x',
and calculate the value of 'y' for each one:

The first value I picked for 'x':  x = 72 
The equation is  y=-3, so when x=72, y=-3.  The point is (72, -3)

The second value I picked for 'x' is:  x = 1
The equation is  y=-3, so when x=1,  y=-3.    The second point is (1, -3).

The third value I picked for 'x' is 4 billion.
The equation is  y=-3, so when x=4 billion, y=-3.  The third point is  (1, -3).

Do you see what's going on here ?  Your original equation didn't even
have 'x' in it, so we could tell right away that when the graph is drawn,
the value of 'y' at every point can't depend on 'x'.

When we simplified the equation and got it in standard form, we found that
the slope of the graph is zero.  That means the graph doesn't rise or fall ...
it's just a horizontal line.  Sure enough, the height of points on the line
doesn't depend on 'x'.  The value of 'y' at every point on the line is  -3 .
8 0
2 years ago
If the formula pictured below is used to find the mean of the following sample, what is the value of N?
Pie

Answer:

Choice D). 8

Step-by-step explanation:

The value on n is simply the number of values or the size of the sample data. In our case, we have a total of 8 data values. The value of n will thus be 8

8 0
3 years ago
Read 2 more answers
H2 + 7h + 10 = 0<br> Help please
Leni [432]

Answer:

-2, -5

Step-by-step explanation:

h2 + 7h + 10 = 0

h^2 +7h + 10 = 0

h^2 +2h +5h + 10 = 0

h(h+2) + 5(h+2) = 0

h+2 = 0 or h+5 = 0

h = -2 or h = -5

4 0
3 years ago
A bag of skittles has 50 pieces of candy what percentage is orange ps. there are 11 orange skittles
Oliga [24]

Answer:

I think the answer is 22% but I am not sure

Step-by-step explanation:

Percentage solution with steps:

Step 1: We make the assumption that 50 is 100% since it is our output value.

Step 2: We next represent the value we seek with X

Step 3: From step 1, it follows that 100%=50

Step 4: In the same vein, x%=11.

Step 5: This gives us a pair of simple equations:

100%=50(1).

X%=11(2).

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the left hand side of both equations have the same unit; we have

100% / X% = 11 / 50

X = 22%

Step 7: Taking the inverse (or reciprocal) of both sides yields

X% / 100% = 11 / 50

Therefore, 11 is 22% of 50.

5 0
2 years ago
Read 2 more answers
How can the Pythagorean Identity be used to find sin θ, cos θ, or tan θ and the quadrant location of the angle?
Archy [21]

First lets see the pythagorean identities

sin^2 \Theta + cos^2 \Theta =1

So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is

sin^2 \Theta = 1-cos^2 \Theta => sin \theta = \pm \sqrt{1-cos^2 \Theta}

Now we need to check the sign of sin theta

First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.

So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .

5 0
2 years ago
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