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Stells [14]
3 years ago
7

Find the surface area of this triangular prism.

Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0

Answer:

96

Step-by-step explanation:

A=Area

Using the formulas

A= 2A_{b} +(a+b+c)h\\A_{b} = \sqrt{s(s-8)(s-10)(s-6)} \\s= \frac{8+10+6}{2}

Solving for A

A=ah+bh+ch+\frac{1}{2}*\sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4}

A=8(2)+10(2)+6(2)+\frac{1}{2}*\sqrt{-8^{4} +2*(8*10)^{2} +2*(8*6)^{2}-10^{4} +2*(10*6)^{2}-6^{4} }A=96

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fredd [130]
The answer is 117 degrees
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Use conversion factors to find the answer, distance tracked in feet after 12 seconds at 87 miles per hour.
Assoli18 [71]
1 hour=3600 seconds
1 mile=5280 feet
87 miles/hr (1 hr/3600 sec)(5280 ft/mile)=127.6 feet/sec

Distance= Rate*time
d=127.6(12)=1531.2 feet (after 12 seconds) 
3 0
3 years ago
If 15 actuators have failed today, what is the probability that a) at least 10 are repairable? b) from 3 to 8 are repairable? c)
Ann [662]

The probabilities of at least 10 are repairable is 1/3. and probabilities of from 3 to 8 are repairable is 1/5*8/15 and probabilities of exactly 5 are repairable is 1/3.

According to the statement

we have given that If 15 actuators have failed and we have to find the probabilities on some conditions.

we know that the formula of probabilities is

probability = possible outcomes / total outcomes

So,

  • at least 10 are repairable = 1 - (10 are not repairable)

at least 10 are repairable = 1 - 10/15

at least 10 are repairable = (15 - 10)/15

at least 10 are repairable = (5)/15

at least 10 are repairable = 1/3

  • from 3 to 8 are repairable = 3/15 *8/15

from 3 to 8 are repairable = 1/5 *8/15

  • exactly 5 are repairable = 5/15

exactly 5 are repairable = 1/3

These are the probabilities of the given conditions.

So, The probabilities of at least 10 are repairable is 1/3. and probabilities of from 3 to 8 are repairable is 1/5*8/15 and probabilities of exactly 5 are repairable is 1/3.

Learn more about PROBABILITIES here brainly.com/question/25870256

#SPJ4

6 0
2 years ago
Explain why the X coordinates of the points where the graphs of the equations y=2^-x and y=4^x+3 intersects
sveta [45]
Hello,

y=2^(-x)
y=2^(2x)+3

==>2^(2x)+3=1/2^x
==>2^(3x)+3*2^x-1=0 (1)
Let's assume u=2^x
(1)==>u^3+3*u-1=0

which as 3 roots
u=0.322185354626 or
u = -0.161092677313 + i1.754380959784 or
u = -0.161092677313 - i1.754380959784.

Let's take the real solution

 0.322185354626=2^x
==>x=ln(0.322185354626) / ln(2)
 x=-1,6340371790199...

an other way is
f(x)=2^(3x)+3*2^x-1
f(-2)=1/64+3/4-1=-15/64 <0
f(-1)=1/8+1-1=1/8>0
==> there is a solution betheen -2<x<-1










6 0
3 years ago
Please help 2. Name the polar coordinates of the point graphed below.
Y_Kistochka [10]
A) (-4,2π/3)
b) (4,4π/3)
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