Answer:
- 3rd quadrant: 210°
- 4th quadrant: 330°
Step-by-step explanation:
The equation can be rearranged by subtracting 1, then dividing by 2. Doing so gives you ...
... sin(x) = -1/2
The sine of an angle is the y-coordinate of the point where its terminal ray intersects the unit circle. A horizontal line at y=-1/2 intersects the unit circle in two places. (Refer to the attached diagram.) In each case, the reference angle (the smallest angle made with the x-axis) is 30°.
Conventionally, we measure angles counterclockwise from the +x axis, so the 3rd-quadrant angle (between 180° and 270°) will be 180°+30° = 210°.
The 4th-quadrant angle (between 270° and 360°) will be 360°-30° = 330°.
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<em>Comment on the diagram</em>
The geometry program used to create the figure decided to show the angles measured clockwise. To get the answers you want, you need to subtract the angles shown from 360°.
<em>Comment on calculator solutions</em>
If you use a calculator (in degrees mode) to find the angle whose sine is -1/2, it will tell you sin⁻¹(-0.5) is -30°. This means the angle is 30° measured clockwise from the +x axis. Of course, the value you want in that quadrant is 360°-30° = 330°. You have to understand that the third quadrant angle can be found by adding the reference angle (30°) to 180°.
The width is 37
if the length is 11
and the perimeter is 48 and u need to find the width what u do is
p=48
L=11
48-11=37
so the formula is
2L + 2w=p
11 + 37= 48
Answer:
Step-by-step explanation:
The conic form of the equation for a sideways parabola is
(y - k)² = 4p(x - h)
The focus is at (h + p, k)
The equation of Samara's parabola is
(y - 3)² = 8(x - 4)
h = 4
p = 8/4 = 2
k = 3
h + p = 6
So, the focus point of the satellite dish is at
Answer:
3.81 s
Step-by-step explanation:
Let's consider the following formula that represents the journey of a falling object.
d = 3 t + 5 t²
where,
- d is the distance measured in feet
- t is the time measured in seconds
We can find the time that it will take to travel 84 feet by replacing d = 84 in the equation.
84 = 3 t + 5 t²
5 t² + 3 t - 84 = 0
We have a = 5, b = 3 and c = -84. We apply the second grade solving formula.
x₁ = 3.81 and x₂ = -4.41
Since the time cannot be negative, the answer is t = 3.81 s
Answer:
tenth
Step-by-step explanation: