Answer:
Please go more into depth with this question
We have ( 8 + 4 )/ 2 = 12/2 = 6;
(-2 - 6 ) / 2 = -8 / 2 = -4;
The midpoint is (6,-4);
Answer:
a) 0.1558
b) 0.7983
c) 0.1478
Step-by-step explanation:
If we suppose that small aircraft arrive at the airport according to a <em>Poisson process</em> <em>at the rate of 5.5 per hour</em> and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:
(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?
(b) What is the probability that at least 4 arrive during a 1-hour period?
(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?
If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now
and we want <em>P(X ≥ 75) = 1-P(X<75)</em>. But
hence
P(X ≥ 75) = 1-0.852 = 0.1478
If the perimeter is 13y-5, then it should be equal to all of these sides added together. So, let’s add all of the sides we already know up:
5y-4 + y + 3y+1 = 9y-3.
Now set this equal to the perimeter we already know:
9y-3 = 13y-5. Subtract 9y from both sides.
-3 = 4y-5. Add 3 to both sides.
4y-2.
Now we have the value of 4y-2. Since we know that the last two sides are completely the same, then we can divide this expression by 2.
Therefore, the remaining side is 2y-1.