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Burka [1]
4 years ago
13

Can you exchange the coordinates of points (x1,y 1) and (x2, y2) in the distance formula and still find the correct distance? Ex

plain your answer with an example.
Mathematics
2 answers:
Vikentia [17]4 years ago
5 0
It doesn't matter because, in the end, the differences are squared and multiplying a negative by a negative yields a positive.
Snowcat [4.5K]4 years ago
5 0

Answer:

Yes. we can exchange the coordinates.

Step-by-step explanation:

Distance formula says that

distance between

(x_1, y_1) & (x_2, y_2) = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

and we consider the positive root only

If these two are interchanged when we square the result would be the same.

Example:

(1,2) and (-2, -2)

Distance in one order = \sqrt{(1+2)^2+(2+2)^2} =5

If order is interchanged

distance = \sqrt{(-2-1)^2+(-2-2)^2} =5

Thus we find that order does not matter while calculating distance.

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Solve for c: c=5 5/6 x 2
Marina86 [1]

Hi there!

c=11 2/3

<u><em>1.Convert 5 5/6 into mixed number:</em></u>

<u><em /></u>5 \frac{5}{6}=\frac{35}{6}<u><em /></u>

<u><em>2.Convert 2 into fraction term:</em></u>

<u><em /></u>2=\frac{2}{1}<u><em /></u>

<u><em>3.Convert both fraction into same denominator:</em></u>

<u><em /></u>\frac{35}{6}=\frac{35}{6}<u><em /></u>

<u><em /></u>\frac{2}{1}=\frac{12}{6}<u><em /></u>

<u><em>4.Multiply the two terms:</em></u>

<u><em /></u>\frac{35}{6}<u><em>·</em></u>\frac{12}{6}=\frac{70}{6}<u><em /></u>

<u><em>5.Simplfly the fraction term:</em></u>

<u><em /></u>\frac{70}{6}=\frac{35}{3}<u><em /></u>

<u><em /></u>\frac{35}{3}=11 \frac{2}{3}<u><em /></u>

Therefore, c=11 2/3.

<u><em /></u>

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