All categories

3 years ago

If an x-coordinate repeats, can a relation still be a function?I need help right now

Mathematics

1 answer:

Gre4nikov [31]3 years ago

8 0

Answer:

Step-by-step explanation:

if you see any duplicates or repetitions in the x-values, the relation is not a function.

You might be interested in

If you run a marathon of 26 1/5 miles in a time of 5 4/5 how far do you run in 1 hour<br><br>pls

alisha [4.7K]

First let's make both the miles and the hours ran improper fractions:

$26+\frac{1}{5}=\frac{131}{5}\\ 5+\frac{4}{5}=\frac{29}{5}$

So, to find our miles per hour, we have to divide the miles by the hours to get: $\frac{\frac{131}{5}\text{miles}}{\frac{29}{5}\text{hours}}=\frac{131\text{miles}}{29\text{hours}} \\ \text{ Now we have to divide the top and the bottom by 29 to get our miles per hour so: }\\ \frac{\frac{131}{29}}{\text{hour}} \approx \frac{4.52 \text{miles}}{\text{hour}}$

8 0

3 years ago

Help for brainliest plz

Illusion [34]

Answer:

500

Step-by-step explanation:

Equations =4÷3×3.14×5×5×5

6 0

3 years ago

Read 2 more answers

Two faulty machines, M1 and M2, are repeatedly run synchronously in parallel (i.e., both machines execute one run, then both exe

leonid [27]

The event that either M1 or M2 fails has probability

$P(M_1\text{ fails or }M_2\text{ fails})=P(M_1\text{ fails})+P(M_2\text{ fails})-P(M_1\text{ and }M_2\text{ both fail})$

by the addition rule. Failure events are independent, so

$P(M_1\text{ and }M_2\text{ both fail})=P(M_1\text{ fails})P(M_2\text{ fails})$

so that

$P(M_1\text{ fails or }M_2\text{ fails})=p_1+p_2-p_1p_2$

Denote this probability by $p$ . Then $X$ follows a geometric distribution with this parameter $p$ and has density

$P(X=x)=\begin{cases}(1-p)^{x-1}p&\text{for }x\ge1\\0&\text{otherwise}\end{cases}$

The expectation is $\dfrac1p=\dfrac1{p_1+p_2-p_1p_2}$ .

7 0

4 years ago

A car travels 30 1/5 miles in 2/3 of an hour. Whwt is the average speed, in miles per hour, of the car

LiRa [457]

Answer:

45 3/10 mph

Step-by-step explanation:

30 1/5 /2 = 15 1/10

15 1/10 x 3 = 45 3/10 mph

8 0

3 years ago

Solve pattern 66 73 13 21 52 _ 10 20

8090 [49]

The answer would be 61. First, if you are trying to figure out the pattern. You must subtract the second number with the first then fourth number with the fifth and so on, you get.

73 minus 66 equals 7.
21 minus 13 equals 8.
XX minus 52 equals x.
20 minus 10 equals 10.

Basing on the pattern of the set of numbers, x will equal 9, To get this you must do 52 and 9 which will equal 61.

4 0

3 years ago