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ValentinkaMS [17]
3 years ago
14

PLEASE HELP FAST YOU WILL GET BRAINLIEST Which is a property of polygons? A polygon has a maximum of 100 sides. A polygon is a p

lane figure. A polygon is a solid figure. A polygon is an open figure.
Mathematics
2 answers:
olganol [36]3 years ago
6 0

Answer:

Sides   Polygon

3    triangle

4   quadrilateral

5    pentagon

6      hexagon

7    heptagon

9    nonagon

10    decagon

idk but hope this helps or not idk


Bezzdna [24]3 years ago
4 0

Answer:

a polygon is a solid figure

Step-by-step explanation:

a solid figure is also known as a closed figure

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6c^3 +30c / 3c^2 + 15
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Hello there,

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3 years ago
How do you know what angle degree goes on each corner?
Dahasolnce [82]

Let'sSo, we gave 2 parallel lines and 2 transversals, we have to match the angles.

Let's start with angle b,

\begin{gathered} b+65=180\text{ (angles in a straight line)} \\ b=180-65 \\ b=115^o \end{gathered}

Let's move on to angle e,

\begin{gathered} e=b\text{ (Vertically opposite angles)} \\ \text{but b = 115}^o \\ e=115^o^{} \end{gathered}

Let's move on to angle d,

d=110^o\text{ (V}ertically\text{ opposite angles)}

Moving to angle c, we have;

c=45^o\text{ (Vertically opposite angles)}

And, angle a;

\begin{gathered} a=b\text{ (Alternate angles)} \\ a=115^o \end{gathered}

8 0
1 year ago
Find an equation of the circle that satisfies the given conditions.
hodyreva [135]
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

P(-1,1) \\
x_1=-1 \\ y_1=1 \\ \\ Q(5,9) \\ x_2=5 \\ y_2=9 \\ \\
\frac{x_1+x_2}{2}=\frac{-1+5}{2}=\frac{4}{2}=2 \\ \frac{y_1+y_2}{2}=\frac{1+9}{2}=\frac{10}{2}=5

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(-1,1) \\ x_1=-1 \\ y_1=1 \\ \\ (2,5) \\ x_2=2 \\ y_2=5 \\ \\ d=\sqrt{(2-(-1))^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5

The radius is 5.

(x-2)^2+(y-5)^2=5^2 \\
\boxed{(x-2)^2+(y-5)^2=25}
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2 years ago
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