Answer:
152.7 yd
Step-by-step explanation:
I presume that there is a fence around the perimeter and separating the various plots.
AG = BF = CE = 18 yd
GH = DE = 12 yd
EO² = DE² + DO²
1 5² = 12² + DO²
225 = 144 + DO²
81 = DO²
DO = 9
BC = DO = EF = 9 yd
AC = DH = EG = 17 yd
AO² = AB² + BO² = 8² + 6² = 64 + 36 =100
AO = √100 = 10 yd
CO² = BC² + BO² = 9² + 6² = 81 + 36 = 127
CO = √127 yd
GO² = FG² + FO² = 8² + 12² =64 + 144 = 208
GO = √208 = 4√13 yd
Fencing needed
= (AC + DH + EG) + (AG + BF + CE) + AO + CO + EO + GO
= (3 × 17) + 3 × 18) + 10 + √127 + 15 + 4√13
= 51 + 54 + 25 + 11.27 + 14.42
= 152.7 yd
A) x - 7 > 3 |add 7 to both sides
x > 10
b) x - 7 > 3 |add 7 to both sides
x > 10
Answer:
the aawnse is c
Step-by-step explanation:
Answer:
1. 128 pages.
2. (y - x) + 1
3. 6 pages.
4. Helps to formulate the expression for the number of pages read.
Step-by-step explanation:
1. George will read pages 385 through 512 in his karate history book. And we are asked to find the number of pages that he will read.
The required number of pages that George read will be = (512 - 385) + 1 = 128 pages.
2. If he read from page number x through page number y then the general rule of finding the number pages that he read will be = (y - x) + 1
3. If x = 500 and y = 505, then the number of pages read is = (505 - 500) + 1 = 6 pages.
Again, if x = 5 and y = 29, then again the number of pages read is = (29 - 5) + 1 = 25 pages.
4. The rule just formulates the expression for the number of pages read and it eases the calculation for the number of pages read. (Answer)
Answer:I think it 20 adult to 50 kids
Step-by-step explanation:
