Answer:
27.33333... mph
Step-by-step explanation:
Find 1/3 of 20 1/2: 1/3*41/2=41/6
That equals 6.83333...
Now add 20 1/2 and 6.83333 = 27.3333...
Therefore, 27.33333... mph
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
A line that passes through an angle and splits it into two equal adjacent angles
My answer is C
because
x-12=-3
x=-3+12
x=9
The answer is option (c) 7xy^2-2xy^2
