Treat

as the boundary of the region

, where

is the part of the surface

bounded by

. We write

with

.
By Stoke's theorem, the line integral is equivalent to the surface integral over

of the curl of

. We have

so the line integral is equivalent to


where

is a vector-valued function that parameterizes

. In this case, we can take

with

and

. Then

and the integral becomes


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Answer:
Hence the carnival game gives you better chance of winning.
Step-by-step explanation:
Let the event of win be given by 1/10 in the game of rifle then the event of loose is given by 9/10
the
Odds in favor of a game are given by = P(Event)/ 1- P(Event)
Odds in favor of winning a rifle are given by = 1/10/ 1- 1/10
=1/10/9/10
=1/9
= 0.111
The probability of winning aa rifle game is 0.111
The probability of winning the carnival game is 0.15
Comparing the two probabilities 0.111:0.15
The probability of winning carnival game is greater than winning a rifle game
0.15>0.11
Hence the carnival game gives you better chance of winning.
Answer:
C
Step-by-step explanation:
Answer:
0.11069
Step-by-step explanation:
We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.
P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

I hope that works for you!
Answer:
Company B
Step-by-step explanation:
We would use z score formula
z = (x - μ) / σ
x = raw score
μ = mean
σ = Standard deviation
let x = 260 with the mean μ1 = 276 and standard deviation σ = 5.8
let x = 260 with the mean μ2 = 252 and standard deviation σ = 3.4
z1 = (x- μ1) / σ = (260- 276) / 5.8 = -2.7586206897 = -2.76
z2 = (x2 - μ) / σ = (260 -252) / 3.4= 2.3529411765 = 2.35
Comparing the two z scores, we can see that company B has the probability of producing 260 nails because it has a z score of 2.35 compared to company A with a z score of -2.76.