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3 years ago

Choose the correct missing coefficient to balance the following equation:

Chemistry

2 answers:

nikitadnepr [17]3 years ago

7 0

Answer:

Explanation:

We want to balance the equation. On the right, there are 4 hydrogens, and 2 oxygens. We should have the same amount on the left.

For hydrogens, we want 4. 2 *2 =4,

Therefore, the answer is 2

<em>I hope this helps! :)</em>

Fittoniya [83]3 years ago

6 0

Answer:

Explanation:

because it helps to balance the equation

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If 50.0 g of KCl reacts with 50.0 g of O2 to produce KClO3 according to the following equation, how many grams of KClO3 will be

Sliva [168]

Answer:

A. 82.2g of KClO3

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3

C. Formula equation:

2KCl + 3O2 —> 2KClO3

Explanation:

The balanced equation for the reaction. This is given below:

2KCl + 3O2 —> 2KClO3

Next, we shall determine the masses of KCl and O2 that reacted and the mass of KClO3 produced from the balanced equation. This is illustrated below:

Molar Mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g

Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Summary:

From the balanced equation above:

149g of KCl reacted.

96g of O2 reacted.

245g of KCl were produced.

Next, we shall determine the limiting reactant. This is illustrated below:

From the balanced equation above,

149g of KCl reacted with 96g of O2.

Therefore, 50g of KCl will react with = (50 x 96)/149 = 32.21g of O2.

Since a lesser mass of O2 ( i.e 32.21g) than what was given (i.e 50g) is needed to react completely with 50g of KCl, therefore, KCl is the limiting reactant and O2 is the excess reactant.

A. Determination of the mass of KClO3 produced from the reaction.

In this case the limiting reactant will be used.

From the balanced equation above,

149g of KCl reacted To produce 245g of KClO3.

Therefore, 50g of KCl will react to produce = (50 x 245)/149 = 82.2g of KClO3.

Therefore, 82.2g of KClO3 is produced from the reaction.

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3.

C. Formula equation:

2KCl + 3O2 —> 2KClO3

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4 years ago

What is a polar liquid?

BabaBlast [244]

Polar liquids have both negative and positive ends.

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4 years ago

Read 2 more answers

A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla

mezya [45]

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times }{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

moles of $BaCl_2$ (solute) = $\frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L$

Therefore, the molarity of solution is 1.20 mol/L

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3 years ago

What is the best solution to groundwater depletion?

atroni [7]

<span>Ground water depletion is one of the major problems. The best solution is to conserve water that we are having currently and to recycle those wasted water. water conservation can be done in many ways such as reduce the level of pumping the ground water, avoiding the use of chemicals, use of natural fertilizers, rain water saving, pumping water to the tanks from stored rain water in the ground, way of handling the water consuming jobs.</span>

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3 years ago

Water heater contains 56 part a how many kilowatt-hours of energy are necessary to heat the water in the water heater by 25 ?c?

DochEvi [55]

Answer is: 550,021 kWh of energy is needed to heat the water

V(water) = 51 gal = 51·3,78 = 189,3 L.

ΔT(water) = 25°C.

d(water) = 1000 g/L.

m(water) = V(water) · d(water)

m(water) = 189,3 L · 1000 g/L

m(water) = 189300 g.

Q = m(water) · ΔT(water) · C(water)

Q = 189300 g · 25°C · 4,184 J/°C·g

Q = 19800780 J = 19800,78 kJ ÷ 3600 = 550,021 kWh.

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3 years ago