1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maslowich
3 years ago
6

A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla

sk to the mark with water. Calculate the concentration in of the chemist's barium chloride solution. Round your answer to significant digits.
Chemistry
1 answer:
mezya [45]3 years ago
8 0

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times }{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of BaCl_2(solute) = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L

Therefore, the molarity of solution is 1.20 mol/L

You might be interested in
When the surface water temperature is still well below the water boiling temperature, some bubbles at the bottom tend to float u
irga5000 [103]

Answer:

The reasons why the seemingly floating bubbles disappear was that they tend to loss their latent heat to the water molecules at the surface water.

Explanation:

Heat energy has a considerable effect on the velocity of molecules including water. The water molecules below the container will receive much more heat energy than those above it. This heat energy in the form of specific heat capacity and latent heat that result in the increase in the speed of individual molecules of water and finally to the escape of the molecules to a colder region of the container, in this case the upper region. At the collision of the bottom water to the surface water, they tend to exchange their heat content, the hotter molecules will lose their heat to the cold ones. When the formerly hot molecules encounter this, it will result in lowering the temperature and consequentially to the reduction of their movement, once in the form of bubble, now become ordinary water. This convectional transfer of heat energy will continue until the whole system has a uniform temperature depending on the consistency of the heat source.

7 0
3 years ago
What does the second law of thermodynamics say? O A. The entropy of the universe is increasing. B. A system at equilibrium has n
gayaneshka [121]

Answer:

A.  The entropy of the universe is increasing.(always)

Explanation:

The Second Law of Thermodynamics states that Entropy cannot decrease, because it keeps increasing and increasing and increasing. It will always stay on the increasing side.

<u><em>Hope this helps!</em></u>

<u><em>Please Mark Brainliest!</em></u>

7 0
3 years ago
7. A 2.0 L container had 0.40 mol of He(g) and 0.60 mol of Ar(g) at 25°C.
Finger [1]

Answer:

a) Ek Ar > Ek He

b) v Ar < v He

c) If v Ar = 431 m/s ⇒ v He = 1710.44 m/s

d) Pt = 12.218 atm

e) P He = 4.887 atm and P Ar = 7.33 atm

Explanation:

container:

∴ V = 2.0 L

∴ n He = 0.4 mol

∴ n Ar = 0.6 mol

∴ T = 25°C ≅ 298 K

a) Internal energy (U) :

∴ U = Ek + Ep = kinetic energy + potential energy

∴ Ep: the potential interaction energy is neglected, assuming ideal gas mixture

⇒ U = Ek = N(1/2mv²)= 3/2 NKT

∴ N = nNo ....number of moleculas

∴ K = 1.380 E-23 J/K....Boltzmann's constant

∴ No = 6.022 E23 molec/mol....Avogadro's number

for He:

⇒ N = (0.4)(6.022 E23) = 2.4088 E23 molec

⇒ Ek = (3/2)(2.4088 E23)(1.380 E-23 J/K)(298) = 1485.892 J

for Ar:

⇒ N = (0.6)(6.022 E23) = 3.6132 E 23 molec

⇒ Ek = (3/2)(3.6132 E23)(1.380 E-23 J/K)(298) = 2228.838 J

** Ar gas has a greater average kinetic energy

b) He:

∴ N(1/2)mv² = (3/2)NKT

⇒ mv² = 3KT

⇒ v² = 3KT/m

⇒ v = √3KT/m

∴ m He = (0.4 mol)(4.0026 g/mol) = 1.601 g He = 1.601 E-3 Kg He

⇒ v = √(3(1.380 E-23)(298)/(1.601 E-3)) = 2.776 E-9 m/s He

Ar:

∴ m Ar = (0.6)(39.948 g/mol) = 23.969 g = 0.0239 Kg Ar

⇒ v = 6.99 E-10 m/s

** v Ar < v He

c) r = V Ar / v He = (6.99 E-10 m/s)/(2.776 E-9 m/s) = 0.252

∴ If v Ar = 431 m/s

⇒ v He = v Ar/0.252 = 431 m/s / 0.252 = 1710.44 m/s

d) Pt = ntRT / V

∴ nt = 0.4 + 0.6 = 1 mol

⇒ Pt = (1mol)(0.082 atm.L/K.mol)(298 K)/(2.00 L) = 12.218 atm

e) P He = nRT/V = (0.4)(0.082)(298)/2 = 4.8872 atm

⇒ P Ar = Pt - PHe = 12.218 - 4.8872 = 7.33 atm

3 0
3 years ago
Aryan want to deposit silver on an iron spoon using silver nitrate as electrolyte. Which terminal of the battery he should conne
34kurt

Silver from the anode gets dissolved to reach the cathode, where the spoon will be plated.

<h3>What is electroplating?</h3>

Electroplating is a way of electrolysis, where a thin layer of metal is used to plate a determined object. It is a kinda process to purify a material you want.

The anode contains the metal you want to plate with, in this case, the Ag.

The anode contains the half-reaction of oxidation so:

Ag(s) → Ag ⁺ (aq)  +  e⁻

In the cathode, you have the spoon, which it takes place the half-reaction of reduction:

Ag ⁺ (aq)  +  e⁻  →  Ag(s)

The electrolytic cell, where the redox reaction takes place, must be filled with a AgNO₃ solution.

Silver from the anode gets dissolved to reach the cathode, where the spoon will be plated.

Learn more about the electroplating here:

brainly.com/question/20112817

#SPJ1

8 0
2 years ago
650. J is the same amount of energy as A. 155 cal. B. 2720 calC. 650 cal.D. 1550 cal.
sladkih [1.3K]

Answer:

A\text{ : 155 cal}

Explanation:

Here, we want to convert J to cal

Mathematically:

1\text{ cal = 4.186 J}

Thus, to get our answer in cal, we divide the value given by 4.186

We have that as:

\frac{650}{4.186}\text{ = 155 cal}

5 0
1 year ago
Other questions:
  • Which of the following is true of liquids and solids?
    14·1 answer
  • Explain different ways you could increase the reaction rate, and/or decrease the reaction rate
    5·1 answer
  • 2. What are the similarities between law of triads and law of octaves?​
    10·1 answer
  • Please Help Assap!!!
    15·1 answer
  • How many moles of AlCl3 are in 2.25L of a 0.15 molar solution?
    8·1 answer
  • One molecule of the spherically shaped, oxygen‑carrying protein in red blood cells, hemoglobin, has a diameter of 5.5 nm 5.5 nm
    11·1 answer
  • What is Metabolism?
    15·2 answers
  • 28. How many formula units are found in 0.250 moles of potassium nitrate?
    9·1 answer
  • Question 18
    9·1 answer
  • In an experiment magnesium ribbon was heated in air. The product was found to be heavier than the original ribbon. Potassium man
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!