Answer:
sp³
Explanation:
Number of hybrid orbitals = ( V + S - C + A ) / 2
Where
H is the number of hybrid orbitals
V is the valence electrons of the central atom = 5
S is the number of single valency atoms = 4
C is the number of cations = 1
A is the number of anions = 0
For PCl₄⁺
Applying the values, we get:
H = ( 5+4-1+0) / 2
= 4
<u>This corresponds to sp³ hybridization.</u>
Zn⁰ ----> Zn⁺² + 2e⁻ - oxidation
Hg⁺² + 2e⁻ ----> Hg⁰ - reduction
Zn loses 2 moles of electrons , and Hg gains 2 mole of electrons.
So, number of moles of electrons gained and lost during reaction is equal.
Answer:
33/7
Multiply the denominator of the fraction by the whole number.
Add this result to the numerator of the fraction
answer becomes the numerator of the improper fraction.
Explanation:
