Solve for x (round to the nearest thousandth)

11 Pause

muminat

Answer:

Step-by-step explanation:

Given that:

Batting average = 0.25 after 160 times at bat;

Batting Average = Number of hits / number of times at bat

0.25 = number of hits / 160

Number of hits = 0.25 * 160 = 40

He want batting average to improve to 0.333 ; if he makes hit the next x times at bat ; number of hits is needed to improve batting average

Hence,

New average = number of hits / number of times at bat

0.333 = (number of hits + x) / (160 + x)

0.333 = (40 + x) / (160 + x)

6 0

3 years ago

Multiply. -3 2/3 x - 2 1/4. choices -8 1/4 -6 1/6 6 1/6 or 8 1/4

Artemon [7]

Answer:

8 1/4

Step-by-step explanation:

3 0

3 years ago

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Se generan ondas, introduciendo en agua el borde de una regla 15 veces en 3.0 segundos. Calcular: a) el periodo de las ondas b)

Ne4ueva [31]

Answer:

Ver explicacion

Step-by-step explanation:

La frecuencia de una onda se define como el número de ciclos completos que realiza una partícula en un segundo.

f = n / t = 15 ciclos / 3 segundos = 5 ciclos por segundo o Hertz

El período de una onda es el tiempo que tarda la onda en realizar una oscilación o ciclo completo.

T = t / n = 3/15 = 0,2 segundos

6 0

3 years ago

For a quality control test, a company checks the miles per gallon (mpg) for a simple random sample of 100 minivans drawn from it

amm1812

Answer:

95% confidence interval for the average mpg of all minivans in the company's inventory is [15.22 mpg , 15.98 mpg].

Step-by-step explanation:

We are given that a company checks the miles per gallon (mpg) for a simple random sample of 100 minivans drawn from its current inventory.

The average mpg of these 100 minivans is 15.6 with a standard deviation of 1.9 mpg.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average mpg = 15.6 mpg

s = sample standard deviation = 1.9 mpg

n = sample of minivans = 100

$\mu$ = population average mpg

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.</em>

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.987 < $t_9_9$ < 1.987) = 0.95 {As the critical value of t at 99 degree

of freedom are -1.987 & 1.987 with P = 2.5%}

P(-1.987 < $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ < 1.987) = 0.95

P( $-1.987 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X -\mu}$ < $1.987 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.987 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.987 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for</u> $\mu$ = [ $\bar X-1.987 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.987 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $15.6-1.987 \times {\frac{1.9}{\sqrt{100} } }$ , $15.6+1.987 \times {\frac{1.9}{\sqrt{100} } }$ ]

= [15.22 mpg , 15.98 mpg]

Therefore, 95% confidence interval for the average mpg of all minivans in the company's inventory is [15.22 mpg , 15.98 mpg].

It is appropriate to compute a confidence interval for this problem using the Normal curve as t test statistics is used when data should follow normal distribution.

7 0

3 years ago

If you add three to me and Divide me by four and get four what am I

natali 33 [55]

Answer:

2 in think

Step-by-step explanation:

6 0

2 years ago

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