This seems like a personal question
4n/4n-4 × n-1/n+1
= 4n(n-1)/(4n-4)(n+1)
= (4n^2 - 4n)/(4n^2 + 4n - 4n-4)
= (4n^2 - 4n)/(4n^2 - 4)
= 4(n^2 - n)/4(n^2 - 1)
=(n^2 - n)/(n^2 - 1)
Answer:y = -3x + 10
Step-by-step explanation:
To find an equation of a line that passes through two points, we have to first find the slope between the two equation. We can do this by using the slope formula:
where (x₁, y₁) and (x₂, y₂) are the two points that we are finding the slope between.
Lets make (x₁, y₁) equal to (0, 10) and (x₂, y₂) equal to (3, 1). Now we plug them into the slope formula:
So the slope between the two points is -3.
From here, I would normally take one of the points given to us and plug in the point and slope into the point-slope form of a line and then simplify until we get it in slope-intercept form. But if you look carefully, the y-intercept is given to us as the point (0, 10). So we now know that the y-intercept of the line is 10. We can now take the y-intercept and the slope and plug it into the slope-intercept form of a line to get out equation:
y = mx + b
plug in -3 for m (the slope) and 10 for b (the y-intercept)
y = -3x + 10
So now we have our equation.
I hope you find my answer and explanation helpful. Happy studying. :)
