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3 years ago

Kenny types 280 words. How long did he type for? A.4 B. 5 C.6 D. 7

Mathematics

2 answers:

damaskus [11]3 years ago

6 0

A. 4

Brainly want 20 words ✋

zlopas [31]3 years ago

5 0

Are you sure you didn’t miss anything while writing the question?

Cause we have nothing to go off. Everybody types differently so there is no way for us to say how long he typed for, unless we were given aprox how many words he wrote in a minute or something

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Jayden has $1.20 worth of nickels and dimes. He has twice as many nickels as dimes. Determine the number of nickels and the numb

melamori03 [73]

Answer:

Total number of dimes=6

Total number of nickels=12

Step-by-step explanation:

The expression for the total value of money Jayden has is;

Nickels have a value of= $0.05

Dimes have a value of= $0.10

Total value=(value of nickels×number of nickels)+(value of dimes×number of dimes)

where;

Total value=$1.20

Value of a nickel=$0.05

number of nickels=y, but y=2 x

Value of a dime=0.10

number of dimes=x

replacing;

1.20=(0.05×2 x)+(0.1×x)

0.1 x+0.1 x=1.2

0.2 x=1.2

x=1.2/0.2

x=6

y=2 x=2×6=12

Total number of dimes=6

Total number of nickels=12

7 0

3 years ago

the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?

Soloha48 [4]

Given:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

General term:

The general term of the geometric sequence is given by

$a_n=a(r)^{n-1}$

where a is the first term and r is the common ratio.

The 11th term is given is

$a_{11}=a(4)^{11-1}$

$48=a(4)^{10}$ ------- (1)

The 12th term is given by

$192=a(4)^{11}$ ------- (2)

Value of a:

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

$48=a(1048576)$

Dividing both sides by 1048576, we get;

$\frac{3}{65536}=a$

Thus, the value of a is $\frac{3}{65536}$

Value of the 10th term:

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term $a_n=a(r)^{n-1}$ , we get;

$a_{10}=\frac{3}{65536}(4)^{10-1}$

$a_{10}=\frac{3}{65536}(4)^{9}$

$a_{10}=\frac{3}{65536}(262144)$

$a_{10}=\frac{786432}{65536}$

$a_{10}=12$

Thus, the 10th term of the sequence is 12.

8 0

3 years ago

We're working with single variable equations and I'm okay at them, but I'm rusty when it comes to using it with fractions. If an

jasenka [17]

Answer: v=-18/5

Step-by-step explanation:

Assuming you want to solve for v, we need to use our algebraic properties.

$\frac{v}{3}+2=\frac{4}{5}$ [subtract both sides by 2]

$\frac{v}{3}=-\frac{6}{5}$ [multiply both sides by 3]

$v=-\frac{18}{5}$

Now, we know that v=-18/5.

3 0

3 years ago

Janine plans to deposit $20,000 at the end of each year for eight years into an investment account. The mutual funds containing

Leto [7]

Answer:

$197,949.40

Step-by-step explanation:

Just took the quiz.

3 0

3 years ago

From a group of 13 women and 12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can

Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

= 13!/5!.8!

= 1287

12C₈ = 12!/(12₋8)! 8!

= 12!/5! 8!

= 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

brainly.com/question/11732255

#SPJ10

4 0

2 years ago